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klemol [59]
3 years ago
14

Please help me with a) b) d) do I have to keep Ching Ching

Mathematics
1 answer:
yanalaym [24]3 years ago
5 0
If it's not clear or if you don't understand it, pls tell me

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If f(x)=x-5, find x when f(x)=15
Leya [2.2K]

Answer:

x = 20

Step-by-step explanation:

we are given the value of f(x), replace it in the first equation

15 = x - 5

solve for x by adding 5 on both sides

15 + 5 = x

20 = x or x = 20

5 0
3 years ago
How would I solve I need to know Asap and what is the answer
masha68 [24]

Answer:

True; True; False; True

Step-by-step explanation:

4 0
2 years ago
In a basketball game Fintan made 16 baskets. Each of the baskets is worth either 2 or 3
jekas [21]
Let x represent a 2-point basket, and y represent a 3-point basket.

Basket equation: x + y = 16
Point equation 2x + 3y = 39

Solve using system of equations:
if x + y = 16, then x = 16 - y

Plug into the second equation:
2(16-y) + 3y = 39
32 - 2y + 3y = 39
32 + y = 39
y = 7

So the number of 3-point baskets scored was 7. Hope this helps, let me know if there’s a step you don’t understand! :)
8 0
3 years ago
PLZ ASWER ASAP!!!!!!!!!!!
geniusboy [140]

Answer:

f(x) = 6x² - 24x + 21

Step-by-step explanation:

The equation of a quadratic function in vertex form is

f(x) = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k ) = (2, - 3 ) , then

f(x) = a(x - 2)² - 3

To find a substitute (1, 3 ) into the equation

3 = 1(1 - 2)² - 3

3 = a(- 1)² - 3

3 = a - 3 ( add 3 to both sides )

6 = a

f(x) = 6(x - 2)² - 3 ← in vertex form

     = 6(x² - 4x + 4) - 3

     = 6x² - 24x + 24 - 3

f(x) = 6x² - 24x + 21 ← in standard form

4 0
3 years ago
Equation editor does not include the grouping symbols “<“ and “>” that are necessary for writing a vector in component for
Scilla [17]

Answer:

{12,2}

Step-by-step explanation:

From the given graph it is clear that the initial point of the vector is (-5,0) and the terminal point (7,2).

If initial point of a vector is (x_1,y_1) and terminal point is (x_2,y_2), then

\overrightarrow{v}=(x_2-x_1)i+(y_2-y_1)j

Using this formula, we get

\overrightarrow{v}=(7-(-5))i+(2-0)j

\overrightarrow{v}=12i+2j

\overrightarrow{v}=

Using braces, we get

\overrightarrow{v}=\{12,2\}

Therefore, the required vector is {12,2}.

4 0
3 years ago
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