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KATRIN_1 [288]
3 years ago
13

Item 8 The nutrition facts label on a container of dry roasted cashews indicates there are 161 calories in 28 grams. You eat 9 c

ashews totaling 12 grams.
Mathematics
1 answer:
lakkis [162]3 years ago
5 0
Hey there,
Since your question is not clear, i could only come up with a few possibilities of what you are asking.
1) Weight of 1 cashew
9 cashew = 12 grams
1 cashew = 12 / 9
                = 1.3 grams
2) Calories per gram
28 grams = 161 calories
1 gram = 161 / 28 
            = 5.75 calories
3) Calories for 9 cashews
1 gram = 5.75 calories
12 grams = 5.75 x 12
                = 69 calories

Hope this helps :))

<em>~Top♥</em>
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SOVA2 [1]

Answer:

-4x + y + 6z

Step-by-step explanation:

Combine like terms (Terms with the same variable):

(2x + 5y - z) + (-6x - 4y + 7z)

Add straight across:

2x - 6x = -4x

5y - 4y = y

-z + 7z = 7z - z = 6z

-4x + y + 6z is your answer.

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8 0
3 years ago
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The probability that event A occurs is 0.4, and the probability that events A and B both occur is 0.25. If the probability that
ICE Princess25 [194]

Answer:

The probability that event B will occur is 0.45

Step-by-step explanation:

Given;

probability that event A occurs, P(A) = 0.4

the probability that events A and B both occur, P(A ∩ B) = 0.25

the probability that either event A or event B occurs, P(A ∪ B) = 0.6

To determine the probability that event B will occur, we use probability addition rule;

P(A) + P(B) = P(A ∩ B) + P(A ∪ B)

0.4 + P(B) = 0.25 + 0.6

0.4 + P(B) = 0.85

P(B) = 0.85 - 0.4

P(B) = 0.45

Therefore, the probability that event B will occur is 0.45

4 0
3 years ago
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Alex73 [517]

Answer:

7

Step-by-step explanation:

2v ÷ e + 3

we want to find the value of the expression when v = 10 and e = 5

to do so we substitute the values into the expression

2v ÷ e + 3

==> substitute 10 for v and 5 for e

2(10) ÷ 5 + 3

We now evaluate using bpemdas

==> multiply 2 and 10

20 ÷ 5 + 3

==> divide 20 by 5

4 + 3

==> add 4 and 3

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6 0
2 years ago
Let f(x) = 1/x^2 (a) Use the definition of the derivatve to find f'(x). (b) Find the equation of the tangent line at x=2
Verdich [7]

Answer:

(a) f'(x)=-\frac{2}{x^3}

(b) y=-0.25x+0.75

Step-by-step explanation:

The given function is

f(x)=\frac{1}{x^2}                  .... (1)

According to the first principle of the derivative,

f'(x)=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}

f'(x)=lim_{h\rightarrow 0}\frac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h}

f'(x)=lim_{h\rightarrow 0}\frac{\frac{x^2-(x+h)^2}{x^2(x+h)^2}}{h}

f'(x)=lim_{h\rightarrow 0}\frac{x^2-x^2-2xh-h^2}{hx^2(x+h)^2}

f'(x)=lim_{h\rightarrow 0}\frac{-2xh-h^2}{hx^2(x+h)^2}

f'(x)=lim_{h\rightarrow 0}\frac{-h(2x+h)}{hx^2(x+h)^2}

Cancel out common factors.

f'(x)=lim_{h\rightarrow 0}\frac{-(2x+h)}{x^2(x+h)^2}

By applying limit, we get

f'(x)=\frac{-(2x+0)}{x^2(x+0)^2}

f'(x)=\frac{-2x)}{x^4}

f'(x)=\frac{-2)}{x^3}                         .... (2)

Therefore f'(x)=-\frac{2}{x^3}.

(b)

Put x=2, to find the y-coordinate of point of tangency.

f(x)=\frac{1}{2^2}=\frac{1}{4}=0.25

The coordinates of point of tangency are (2,0.25).

The slope of tangent at x=2 is

m=(\frac{dy}{dx})_{x=2}=f'(x)_{x=2}

Substitute x=2 in equation 2.

f'(2)=\frac{-2}{(2)^3}=\frac{-2}{8}=\frac{-1}{4}=-0.25

The slope of the tangent line at x=2 is -0.25.

The slope of tangent is -0.25 and the tangent passes through the point (2,0.25).

Using point slope form the equation of tangent is

y-y_1=m(x-x_1)

y-0.25=-0.25(x-2)

y-0.25=-0.25x+0.5

y=-0.25x+0.5+0.25

y=-0.25x+0.75

Therefore the equation of the tangent line at x=2 is y=-0.25x+0.75.

5 0
3 years ago
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Ilia_Sergeevich [38]

Answer:AGC and DGH are opposite angles.

Step-by-step explanation:

So, Y+10=3x-40

Y-3x=-50-(1)

3x-40=2x

3x-2x=40

x=40

Y-3x40=-50

y-120=-50

y=-50+120

y=70

Hence, the answer is A 70°

3 0
2 years ago
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