Question

In a volleyball match Hanein serves the volleyball The height of the the ball above the court

Answer 1

(a) The maximum height of the ball above the ground is 12.5 m and the time of motion is 1.43 s.

(b) The time taken for the ball to contact the other player at 0.5 m above the ground is 3.0 s.

Maximum height reached by the ball

The maximum height reached by the ball is calculated as follows.

At maximum height, the final velocity, v = 0

dh/dt = v = 0

dh/dt = -2(4.9)t + 14

0 = -9.8t + 14

9.8t = 14

t = 1.43 s

H(1.43) = -4.9(1.43)² + 14(1.43) + 2.5

H(1.43) = -10.02 + 20.02 + 2.5

H(1.43) = 12.5 m

Time to reach maximum height

12.5 = -4.9t² + 14t + 2.5

4.9t² - 14t + 10 = 0

t = 1.43 s

Time for the ball to reach 0.5 m above the ground

0.5 = -4.9t² + 14t + 2.5

4.9t² - 14t + - 2 = 0

t = 3.0 seconds

The complete question is below:

In a volleyball match Hanein serves the volleyball at 14 m/s, from a height of 2.5 m above the court. The height of the ball in flight is estimated using the equation, h = -4.9t² + 14t + 2.5, where t is the time in second and h is height above ground, in metres.

Learn more about time of motion here: brainly.com/question/2364404

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