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3 years ago

What is the rate of change from 11-12 12-13 13-15 First answer gets brainest

Mathematics

1 answer:

Musya8 [376]3 years ago

8 0

To count for the change you can subtract the numbers

the change from 11 to 12: 61.5 - 59.5 is 2
the change from 12 to 13: 65 - 61.5 is 3.5
the change from 13 to 15 69 - 65 is 4

Hope this helps :)

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Solve for x: 2 over 5 (x − 4) = 2x. −8 negative 1 over 2 1 −1

vlabodo [156]

2/5(x - 4) = 2x
2/5x - 8/5 = 2x....multiply everything by 5
2x - 8 = 10x
-8 = 10x - 2x
-8 = 8x
-8/8 = x
-1 = x <===

5 0

3 years ago

NEED HELP PLZZZZxxxx

nexus9112 [7]

If you use rise/run, the answer is 3/4. Up 3, over 4

8 0

3 years ago

Haley’s work evaluating (Negative 2) Superscript 8 is shown below.

PSYCHO15rus [73]

Answer:

Step-by-step explanation:

The statements are shown below:

A) She used the wrong number as a repeated factor and should have evaluated -2x2x2x2x2x2x2x2.

B) She used the wrong number as a repeated factor and should have evaluated -(8x8).

C) She misinterpreted the exponential form and should have multiplied -2 and 8.

D) She made a sign error when multiplying and should have had 256 as a final answer.

Solution:

The problem to simplify is:

$(-2)^{8}$

Haley's steps are shown below:

$(-2)^{8}=(-2)(-2)(-2)(-2)(-2)(-2)(-2)(-2)=-256$

Generally,

$(a)^b$ is actually "a" multiplied "b" times.

So, Haley wrote "-2" eight times multiplied together. That is okay.

Now,

We are dealing with negative numbers.

When negative numbers are multiplied "odd" number of times, the answer is negative.
When negative numbers are multiplied "even" number of times, the answer is positive.

Haley wrote "-2" eight times, which is EVEN number of times, so the answer would be POSITIVE. But, Haley's answer is negative. Which is wrong. But "256" is right.

Haley's error is:

Answer choice D

6 0

3 years ago

Read 2 more answers

Help I’ll do anything just help

Gnom [1K]

Answer:

$1) {n}^{2} - 81 \\ (n - 9)(n + 9)$

$2) \: \: {a}^{2} - 121 \\ (a - 11)(a + 11)$

$3) \: \: {n}^{2} - 16 \\ (n - 4)(n + 4)$

$4) \: \: 9 {x}^{2} - 144 \\ {3}^{2} {x}^{2} - {12}^{2} \\ (3x - 12)(3x + 12)$

$5) \: 2 {x}^{2} - 9 \\ (2x - 3)(x + 3)$

$6) \: \: 4 {w}^{2} - 9 \\ {2}^{2} {w}^{2} - {3}^{2} \\ (2w + 3)(2w - 3)$

$7) \: \: 4 {n}^{2} - 1 \\ {2}^{2} {n}^{2} - {1}^{2} \\ (2n + 1)(2n - 1)$

$8) \: \: 1 - 16 {x}^{2} \\ {1}^{2} - {4}^{2} {x}^{2} \\ (1 - 4x)(1 + 4x)$

$9) \: \: {x}^{2} - {y}^{2} \\ (x - y)(x + y)$

$10) \: \: 9 - {c}^{2} \\ {3}^{2} - {c}^{2} \\ (3 - c)(3 + c)$

$11) \: \: {n}^{2} - 25 \\ {n}^{2} - {5}^{2} \\ (n + 5)(n - 5)$

$13)49 - 4 {a}^{2} \\ {7}^{2} - {2}^{2} {a}^{2} \\ (7 - 2a)(7 + 2a)$

$14) {a}^{2} {b}^{2} - {c}^{4} \\ (ab - {c}^{2} )(ab + {c}^{2} )$

$15) \: \: 4 {x}^{2} {y}^{2} - 9 {z}^{2} \\ {2}^{2} {x}^{2} {y}^{2} - {3}^{2} {z}^{2} \\ (2xy - 3z)(2xy + 3z)$

hope this helps

sorry, I don't know how solve the 12th one.

thanks.

7 0

3 years ago

Factor each expression

Sophie [7]

1 -since everything includes 4a, we can factor that to get 4a(a-4b^3+2b^2c)
2 - since 5 and 3 add to 8 and multiply to 15, we can do (n+5)(n+3)
3 - since -5 and -4 add to -9 and multiply to 20, we can do (g-5)(g-4)
4 - since -10 and 3 add to -7 and multiply to 30, we can do (z-10)(z+3)
5 - we can factor out 4y to get 4y(y^2-9).

I got the numbers in 2, 3, and 4 with a guesstimating and checking approach

8 0

3 years ago