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3 years ago

Is -2(a-5) equal to -2a-10

Mathematics

2 answers:

Alex777 [14]3 years ago

4 0

-2(a-5)

Multiply the bracket by -2

(-2)(a)(-2)(-5)

-2a+10

Answer: -2a+10 does not equal to -2a-10

AURORKA [14]3 years ago

4 0

Answer:

no the real answer is -2a+10

Step-by-step explanation:

1) do the distributive property:

-2(a-5)

-2a+10

hope this helps!

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Photo attached A. -2 B. -1 C. 1/-2 D. 1/2

kifflom [539]

Step-by-step explanation:

(X1,Y1) = (-2,2)

(X2,Y2) = (0,1)

• Find slope.

m = (Y2 - Y1)/(X2 - X1)

m = (1 - 2)/(0 - (-2))

m = -1/2

The answer is C.

6 0

2 years ago

Look at the diagram. If RS= 8y + 4, ST = 4y + 8, and RT = 36, find the value of y.

vladimir2022 [97]

RS= 8y + 4, ST = 4y + 8, and RT = 36

RS + ST = RT
8y + 4 + 4y + 8 = 36
12y + 12 = 36
12y = 24
y = 2

answer
y = 2 (first choice)

6 0

3 years ago

Read 2 more answers

Bob’a last delivery from Conco oil Company was $125.32. A total of 80.5 gallons was delivered. What was the price per gallon to

julia-pushkina [17]

Answer:

$1.56

Step-by-step explanation:

125.32 : 80.5 = 1.55677 => ~1.56$

5 0

3 years ago

Water pours into a tank at the rate of 2000 cm3/min. The tank is cylindrical with radius 2 meters. How fast is the height of wat

Gennadij [26K]

Volume of water in the tank:

$V=\pi (2\,\mathrm m)^2h=\pi(200\,\mathrm{cm})^2h$

Differentiate both sides with respect to time t :

$\dfrac{\mathrm dV}{\mathrm dt}=\pi(200\,\mathrm{cm})^2\dfrac{\mathrm dh}{\mathrm dt}$

V changes at a rate of 2000 cc/min (cubic cm per minute); use this to solve for dh/dt :

$2000\dfrac{\mathrm{cm}^3}{\rm min}=\pi(40,000\,\mathrm{cm}^2)\dfrac{\mathrm dh}{\mathrm dt}$

$\dfrac{\mathrm dh}{\mathrm dt}=\dfrac{2000}{40,000\pi}\dfrac{\rm cm}{\rm min}=\dfrac1{20\pi}\dfrac{\rm cm}{\rm min}$

(The question asks how the height changes at the exact moment the height is 50 cm, but this info is a red herring because the rate of change is constant.)

7 0

3 years ago

Solve by using Pythagorean Theorem, a= 5, b= x-1, and c=x

charle [14.2K]

The value of x is 13, from the values of x the values of a,b and c becomes 5, 12 and 13, which is obtained by using Pythagorean theorem.

Step-by-step explanation:

The given is,

a = 5

b = x - 1

c = x

Step:1

Pythagorean theorem is,

$a^{2} + b^{2} = c^{2}$ ................................(1)

( It states that the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides )

From the given values the equation (1) becomes,

$5^{2} + (x-1) ^{2} = x^{2}$

( $(a-b)^{2} = a^{2} + b^{2} -2ab$ )

25 + ( $x^{2}$ + 1 - 2x ) = $x^{2}$

25 + 1 -2x = 0 ( ∵ Eliminate $x^{2}$ in both sides)

26 = 2x

x = 13

Step:2

From the values of x,

a = 5

b = ( 13 - 1 ) = 12

c = 13

Result:

The value of x is 13, from the values of x the values of a,b and c becomes 5, 12 and 13, which is obtained by using Pythagorean theorem.

3 0

3 years ago