Answer:
Step-by-step explanation:
<u>Given:</u>
- Speed of the wind = 3 mph
- Speed in calm weather = x
- Speed with the wind = x + 3
- Speed against the wind = x - 3
<u>We know that:</u>
- distance = time*speed or
- time = distance / speed
<u>We have equal time in both cases so comparing d/s ratios:</u>
<u>Solve for x:</u>
- 56(x - 3) = 30(x + 3)
- 56x - 168 = 30x + 90
- 56x - 30x = 90 + 168
- 26x = 258
- x = 258/26
- x ≈ 9.92
<u>The speed with the wind is:</u>
bi(two)...sector(section). Bisector cuts the segment into two equal sections.
BC = CD <em>definition of perpendicular bisector</em>
BC + CD = BD <em>segment addition postulate</em>
CD + CD = BD <em>substitution</em>
2CD = BD <em>added like terms</em>
2CD = 16 <em>substitution</em>
CD = 8 <em>division property of equality</em>
CD = y + 3 <em>given per graph</em>
y + 3 = 8 <em>transitive property</em>
y = 5 <em>subtraction property</em>
Answer: 5
Answer:
6
Step-by-step explanation:
f(x)= x
g(x) = x + 6,
g(f(o))
Let x = 0
f(0) = 0
g(f(0) = g(0) = 0+6 = 6
