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natta225 [31]
3 years ago
10

Help! I’ll reward brainest its pretty easy

Mathematics
1 answer:
DochEvi [55]3 years ago
8 0

Answer:

\frac{3}{10} are wearing blue shirts

Step-by-step explanation:

purple = \frac{2}{5} = \frac{4}{10}

gold = \frac{3}{10}

\frac{4}{10} + \frac{3}{10} = \frac{7}{10}

1 - \frac{7}{10} = \frac{3}{10}

You might be interested in
Spila Motors Inc. earned income of $69,000 from its operating activities for a specified period. During the same period, it sold
11111nata11111 [884]

The right answer is Option C.

Step-by-step explanation:

Income = $69000

Gain = $3000

Total earned= Income + Gain

Total = 69000+3000=\$72000

Expenses on operating activities = $33000

Expenses on non operating activities = $8000

Total expenses = 33000+8000 = $41000

Profit = Total earned - Total expenses

Net\ profit=72000-41000=\$31000

The net profit made by Spila was $31000.

The right answer is Option C.

Keywords: net profit, subtraction

Learn more about subtraction at:

  • brainly.com/question/4279146
  • brainly.com/question/4354581

#LearnwithBrainly

5 0
2 years ago
What is the common ratio for the geometric sequence below, written as a fraction?
MaRussiya [10]
5/8 hope this helps!!
3 0
3 years ago
Read 2 more answers
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
3 years ago
In a random sample of 200 cars of a particular model,
Aleks04 [339]

By using proportions, We expect 150 defects out of the 10,000 cars if the 3 defects out of the 200 cars sampled is representative of all 10,000 cars.

Option A is correct.

First, let's set up the proportions.

A proportion is an equation in which two ratios are set equal to each other.

We have 3/200 cars with defects and we want to know X for X/10000.

So 3/200 = X/10000

Now solve for X.

3/200 = X/10000

X = \frac{3}{200} \times 10000

X = 150

So the answer is: We expect 150 defects out of the 10,000 cars if the 3 defects out of the 200 cars sampled is representative of all 10,000 cars.

Option A is correct.

Find out more information about proportions here

brainly.com/question/11609816

#SPJ4

8 0
1 year ago
Find the midpoint of the line segment shown below.
balu736 [363]

Answer:

x²-6x+y²-4y=-4

Step-by-step explanation:

We know the circle equation stands like this:

(x-a)² + (y-b)² = R²

and (a,b) is center

and R stands for Radius

so in this case:

center = (3,2)

R = 3

So

(x-3)² + (y-2)² = 9

x²-6x+9 + y²-4y+4=9

x²-6x+y²-4y=-4

7 0
2 years ago
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