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saveliy_v [14]
3 years ago
6

Simon has a scale model of the Concorde airplane. The actual length of the Concorde is approximately 200 feet. If the ratio of t

he actual length in feet to the length of the model in centimeters is 5 : 1, what is the approximate length of Simon's model?
Mathematics
2 answers:
Verizon [17]3 years ago
6 0
The answer is:  "40 cm " .
_________________________________________________________
<u>Note</u>:
_________________________________________________________

\frac{200 ft }{ (x) cm} = \frac{5}{1}  ;

Solve for "x" (in "cm" ) ; 


→  5x = 200 * 1 ; 

→  5x = 200 ; 

Divide each side of the equation by "5" ; 
   to isolate "x" on one side of the equation; & to solve for "x" ; 

→  5x / 5 = 200 / 5 ; 

to get:

→  x = 40 .
___________________________________________________________
The answer is:  " 40 cm " .
___________________________________________________________
serious [3.7K]3 years ago
4 0

Answer:the answer is 40cm

Step-by-step explanation:

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Is -3 an expression
Natalija [7]

Answer:

yeah it is an expression

Explanation:

An expression may refer to any of the following:

A combination of letters, numbers, or symbols used to represent a value of a variable. ..

4 0
3 years ago
Five males with an​ X-linked genetic disorder have one child each. The random variable x is the number of children among the fiv
Dahasolnce [82]

Answer and Explanation:

Given : Five males with an​ X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the​ X-linked genetic disorder.

To find :

a. Does the table show a probability distribution?

b. Find the mean and standard deviation of the random variable x.

Solution :

a) To determine that table shows a probability distribution we add up all six probabilities if the sum is 1 then it is a valid distribution.

\sum P(X)=0.029+0.147+0.324+0.324+0.147+0.029

\sum P(X)=1

Yes it is a probability distribution.

b) First we create the table as per requirements,

x      P(x)         xP(x)           x²            x²P(x)

0    0.029         0              0                0

1     0.147        0.147           1              0.147

2    0.324       0.648         4              1.296

3    0.324       0.972         9              2.916

4    0.147        0.588        16              2.352

5    0.029       0.145         25            0.725

   ∑P(x)=1      ∑xP(x)=2.5               ∑x²P(x)=7.436

The mean of the random variable is

\mu=\sum xP(x)=2.5

The standard deviation of the random sample is

Variance=\sigma^2

\sigma^2=\sum x^2P(x)-\mu^2

\sigma^2=7.436-(2.5)^2

\sigma^2=7.436-6.25

\sigma^2=1.186

\sigma=\sqrt{1.186}

\sigma=1.08

Therefore, The mean is 2.5 and the standard deviation is 1.08.

5 0
3 years ago
Write an equation of the line that passes through the given points.<br> (-1,5) and (2, - 7)
Vanyuwa [196]

Answer:

The equation of the straight line is 4x +y = 1

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given points are (-1,5) and ( 2,-7)

Slope of the line

m =\frac{y_{2}-y_{1}  }{x_{2} -x_{1} }  =\frac{-7-5}{2-(-1)}  = \frac{-12}{3} = -4

slope of the line m = -4

<u><em>Step(ii):-</em></u>

The equation of the straight line passing through the point (-1,5) and having slope 'm' = -4

y - y_{1} = m( x-x_{1} )

y - 5 = -4 ( x-(-1))

y -5 = -4 x -4

4 x + y -5 +4=0

4x +y -1 =0

<u><em>Final answer:-</em></u>

The equation of the straight line is 4x +y = 1

<u><em>  </em></u>

6 0
3 years ago
Use the figure from the example to find the length GH. Assume △DEF ≅ △GHJ.
grandymaker [24]
The two triangles are congruent, so corresponding parts of the two triangles are congruent.
GH is corresponding to DE, so GH=DE=17
8 0
3 years ago
I need helppppppp plzzzzz
Norma-Jean [14]

Answer:

Step-by-step explanation:

4x + 15 = 3

Subtract 15 from both sides

4x + 15 - 15 = 3 - 15

4x = -12

Divide both sides by 4

4x/4 = -12/4

x = -3

Check:

substitute x = -3 in the LHS of the  equation,

4*(-3) + 15 = -12 + 15

                 = 3 = RHS

6 0
3 years ago
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