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andrew-mc [135]
3 years ago
11

What do I put? I am having so much trouble with this.

Mathematics
1 answer:
jek_recluse [69]3 years ago
8 0
12. \frac{3}{4} ,  \frac{9}{12}

13. \frac{4}{10} ,  \frac{4}{100}

16. \frac{3}{9} is already in simplest form.
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At home, 2 out of 5 people have access to board and technology. what percent is this?
Paha777 [63]

Answer:

0.4

Step-by-step explanation:

you just have to divide

2÷5=0.4

5 0
3 years ago
Write a real world situation that can be represented by the expression x - 12 subtraction
Tju [1.3M]
Ed has $37 and decides that he wants to go out to lunch with his friend Barb. They go out to eat, and when it comes time to pay the bill they decide to split it. It will cost Ed $12 to pay his half. How much money will he have left after he pays his share?
3 0
3 years ago
How do you find the answer so confused
alexandr402 [8]
For which question, I can help,
<span>for number 9, parallel lines have the same exact slope, so divide each of them by to isolate the y and then see if the slope (number multiplied by x) is the same as the other problems . PS: focus on the slope, rest of equation doesn't matter in this question</span>
5 0
3 years ago
A tank contains 3,000 L of brine with 15 kg of dissolved salt. Pure water enters the tank at a rate of 30 L/min. The solution is
Shalnov [3]

Answer:

Step-by-step explanation:

Volume of tank is 3000L.

Mass of salt is 15kg

Input rate of water is 30L/min

dV/dt=30L/min

Let y(t) be the amount of salt at any time

Then,

dy/dt = input rate - output rate.

The input rate is zero since only water is added and not salt solution

Now, output rate.

Concentrate on of the salt in the tank at any time (t) is given as

Since it holds initially holds 3000L of brine then the mass to volume rate is y(t)/3000

dy/dt= dV/dt × dM/dV

dy/dt=30×y/3000

dy/dt=y/100

Applying variable separation to solve the ODE

1/y dy=0.01dt

Integrate both side

∫ 1/y dy = ∫ 0.01dt

In(y)= 0.01t + A, .A is constant

Take exponential of both side

y=exp(0.01t+A)

y=exp(0.01t)exp(A)

exp(A) is another constant let say C

y(t)=Cexp(0.01t)

The initial condition given

At t=0 y=15kg

15=Cexp(0)

Therefore, C=15

Then, the solution becomes

y(t) = 15exp(0.01t)

At any time that is the mass.

5 0
3 years ago
( Will give Brainliest) Please Helpp<br> Solve the formula for b. Area of rectangle: A=bh
myrzilka [38]
So get b alone.
A=bh
Divide by h
A/h=b
b is alone
And just to rearrange:
b=A/h
5 0
3 years ago
Read 2 more answers
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