Hi there!
The question sounds really complex, but the mathematical operations behind it is figuratively simple. Here, we are told to find 19 (18.7 rounded up is 19) percent of 1,000. To do this, we can set up a proportion to model the whole scenario.
Now, just solve for x by cross multiplying and simplifying.
Therefore,
190 people out of 1,000 people leave out pertinent information on their IRS forms. Hope this helped and have a terrific day!
Yes it is. It is the only even number that is prime that is multiplied by 1.
Answer:
2.5 pi
Step-by-step explanation:
Comment
If you were trying to get the area of a whole circle, you would use
Area = pi r^2
You have to modify the formula to show that just part of the circle has an area that you are interested in.
The new formula is
Area = (theta/360) pi r^2
Givens
r = 30 cm
theta = 100
Solution
Area = (100 / 360) * pi * r^2 Substitute the givens into this formula
Area = (5 / 18) * pi * 3^2 Expand
Area = (5 / 18) * pi * 9 Cancel 9 into 18
Area = 5/2 * pi
Area = 2.5 * pi
To solve this you must use a proportion like so...
The total number of students that can be chosen are 4,663. This number will represent the whole of one fraction in the proportion. We want to know what percent probability out of these students are engineer, medical doctor/surgeon. This would be considered the part of this fraction. Sum the number of engineering students (615) with medical doctors/surgeons (723) to find this number
723 + 615 = 1,338 students that want to be an engineer or medical doctor/surgeon
Percent's are always taken out of the 100. This means that the other fraction in the proportion will have 100 as the whole and x (the unknown) as the part.
Here is your proportion:
Now you must cross multiply
1,338*100 = 4,663*x
133,800 = 4,663x
To isolate x divide 4,663 to both sides
133,800/4,663 = 4,663x/4,663
28.7 = x
This means that there is a 28.7% of a student with the intent of becoming an engineer or a medical doctor/surgeon to be chosen at random
Hope this helped!
~Just a girl in love with Shawn Mendes
