Question

Find sinθ if cosθ = 3}" align="absmiddle" class="latex-formula">

Answer 1

Answer:

$sin = \frac{\sqrt{5} }{3}$

Step-by-step explanation:

                                             SOH CAH TOA

Where:

s = sin

c = cos

t = tan

o = opposite

a = adjacent

h = hypotenuse  

cos = 2/3 where 2 is adjacent side and 3 is hypotenuse, now find opposite side using a^2 + b^2 = c^2 //c is hypotenuse side

2^2 + b^2 = 3^2

4 + b^2 = 9

b^2 = 9 - 4

b^2 = 5

b = square root (5) = 5^(1/2) //opposite side

sin = O/H

$sin = \frac{\sqrt{5} }{3}$

//Hope it helps.