AgNO3 ( aq ) + NaI ( aq ) = NaNO3 ( aq ) + AgI ( s ) .
Answer:
The correct answer is hydrogen.
Explanation:
Stars in the main sequence will remain in the main sequence as long as their cores contain hydrogen atoms. This is because main sequence stars run on the hydrogen atoms within their core to prevent them from falling to the force of gravity. Once these hydrogen atoms run out, the star is no longer considered a main sequence star, gravity takes hold, and the star collapses.
Answer:
22.1 g
Explanation:
Step 1: Write the balanced equation for the combustion of acetylene
2 C₂H₂ + 5 O₂ ⇒ 4 CO₂ + 2 H₂O
Step 2: Calculate the moles corresponding to 75.0 g of CO₂
The molar mass of CO₂ is 44.01 g/mol.
75.0 g × 1 mol/44.01 g = 1.70 mol
Step 3: Calculate the moles of C₂H₂ required to produce 1.70 moles of CO₂
The molar ratio of C₂H₂ to CO₂ is 2:4. The moles of C₂H₂ required are 2/4 × 1.70 mol = 0.850 mol.
Step 4: Calculate the mass corresponding to 0.850 moles of C₂H₂
The molar mass of C₂H₂ is 26.04 g/mol.
0.850 mol × 26.04 g/mol = 22.1 g
Answer:
Zr. You should be able to see it on a periodic table.
Explanation: