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2 years ago

8

What does acetic anhydride form when it reacts with water?

2 answers:

Stels [109]2 years ago

7 0

What does acetic anhydride form when it reacts with water?

<em>W</em><em>h</em><em>e</em><em>n</em><em> </em><em>a</em><em>c</em><em>e</em><em>t</em><em>i</em><em>c</em><em> </em><em>a</em><em>n</em><em>h</em><em>y</em><em>d</em><em>r</em><em>i</em><em>d</em><em>e</em><em> </em><em>r</em><em>e</em><em>a</em><em>c</em><em>t</em><em>s</em><em> </em><em>w</em><em>i</em><em>t</em><em>h</em><em> </em><em>w</em><em>a</em><em>t</em><em>e</em><em>r</em><em> </em><em>i</em><em>t</em><em> </em><em>f</em><em>o</em><em>r</em><em>m</em><em>s</em><em> </em><em>a</em><em>c</em><em>e</em><em>t</em><em>i</em><em>c</em><em> </em><em>a</em><em>c</em><em>i</em><em>d</em><em>.</em><em> </em><em>I</em><em>n</em><em> </em><em>o</em><em>t</em><em>h</em><em>e</em><em>r</em><em> </em><em>w</em><em>o</em><em>r</em><em>d</em><em>s</em><em>,</em><em> </em><em>T</em><em>h</em><em>e</em><em> </em><em>h</em><em>y</em><em>d</em><em>r</em><em>o</em><em>l</em><em>y</em><em>s</em><em>i</em><em>s</em><em> </em><em>o</em><em>f</em><em> </em><em>a</em><em>c</em><em>e</em><em>t</em><em>i</em><em>c</em><em> </em><em>a</em><em>n</em><em>h</em><em>y</em><em>d</em><em>r</em><em>i</em><em>d</em><em>e</em><em> </em><em>i</em><em>n</em><em> </em><em>p</em><em>r</em><em>e</em><em>s</em><em>e</em><em>n</em><em>c</em><em>e</em><em> </em><em>o</em><em>f</em><em> </em><em>w</em><em>a</em><em>t</em><em>e</em><em>r</em><em> </em><em>f</em><em>o</em><em>r</em><em>m</em><em>s</em><em> </em><em>a</em><em>c</em><em>e</em><em>t</em><em>i</em><em>c</em><em> </em><em>a</em><em>c</em><em>i</em><em>d</em><em>.</em><em> </em>

<u>*</u><u>N</u><u>o</u><u>t</u><u>e</u><u> </u><u>t</u><u>h</u><u>a</u><u>t</u><u>:</u><u>-</u><u> </u><em>I</em><em>t</em><em> </em><em>i</em><em>s</em><em> </em><em>a</em><em>n</em><em> </em><em>e</em><em>x</em><em>o</em><em>t</em><em>h</em><em>e</em><em>r</em><em>m</em><em>i</em><em>c</em><em> </em><em>r</em><em>e</em><em>a</em><em>c</em><em>t</em><em>i</em><em>o</em><em>n</em><em>.</em>

a_sh-v [17]2 years ago

4 0

Answer:

<h2><em>Acetic</em><em> </em><em>Acid</em><em> </em></h2>

Explanation:

When Acetic Anhydride reacts with water, it is an exothermic reaction and acetic acid is produced.

(CH3CO)2O (Acetic Anhydride) + H2O (Water) → 2 CH3CO2H (Acetic Acid)

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If 36 000 kg of full cream milk containing 4% fat is to be separated in a 6 hour period into skim milk with 0.45% fat and cream

Yuri [45]

Answer:

B=5522.33kg/h

C=478.11kg/h

Explanation:

Hi! It's a mass balance. First we have to determine the inflow.

mass flow rate = 36000kg / 6h = 6000kg / h

We define the input variable

- input flow (A) = 6000kg / h

-XgA = percentage of fat in A = 0.04

We define output variables.

- skim milk (B)

-creme (C)

-XgB = fat percentage at B = 0.0045

-XgC = percentage of fat in C = 0.45

Then we can start with the balance.

As a general rule, the mass balance is:

Input = Output

Balance sheet

1) A = B + C

Fat balance

2) A * XgA = B * XgB + C * XgC

Now we can solve.

We replace and clear B in equation 2

6000kg / h * 0.04 = B * 0.0045 + C * 0.45

B = (240kg / h) /0.045-C*0.45/0.0045

3) B = 53333.33kg / h-C * 100

We replace equation 3 in 1 and clear C

A = B + C

6000kg / h = 53333.33kg / h-C * 100 + C

C=(6000kg/h-53333.33kg/h)/(-99)

C=478.11kg/h

We replace C in equation 3 and calculate B

B = 53333.33kg / h-478.11kg/h * 100

B=5522.33kg/h

Then we have the values of the outflows.

C=478.11kg/h

B=5522.33kg/h

7 0

3 years ago

One way of obtaining pure sodium carbonate is through the decomposition of the mineral trona, Na3(CO3)(HCO3)Â·2H2O. 2Na3(CO3)(HC

Leviafan [203]

Answer:

a. 92.4%

Explanation:

Based on the reaction:

2Na₃(CO₃)(HCO₃)·2H₂O(s) → 3Na₂CO₃(s) + CO₂(g) + 5H₂O(g)

To obtain the percent yield you need to obtain moles of trona and calculate thoeretical moles of Na₂CO₃, and the ratio of obtained moles / theoretical moles of Na₂CO₃ give percent yield, thus:

Moles of trona:

1.00 metric ton × (1x10³kg / 1 metric ton) × ( 1000moles /226.03 kg) = <em>4424 moles</em>

The theoretical moles of Na₂CO₃ that produce 4424 moles of trona are (Based on the reaction, 2 moles of trona produce 3 moles of Na₂CO₃):

4424 moles trona × (3 moles Na₂CO₃ / 2 moles trona) = <em>6636 moles of Na₂CO₃.</em>

The obtained moles of Na₂CO₃:

0.650 metric ton × (1x10³kg / 1 metric ton) × (1000 moles / 105.99kg) = <em>6133 moles</em>

The ratio of obtained moles / theoretical moles gives:

6133 moles / 6636 moles = 0.924 = <em>92.4%</em>

I hope it helps!

8 0

3 years ago

Formula for Tricarbon heptabromide.

DiKsa [7]

I believe it would be Au^4Cl8

7 0

3 years ago

The half life for the first order conversion of A to B is 56.6 hours. How long does it take for the concentration of A to decrea

sveta [45]

Answer:

It will take 188.06 hours for the concentration of A to decrease 10.0% of its original concentration.

Explanation:

A → B

Initial concentration of the reactant = x

Final concentration of reactant = 10% of x = 0.1 x

Time taken by the sample, t = ?

Formula used :

$A=A_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}$

where,

$A_o$ = initial concentration of reactant

A = concentration of reactant left after the time, (t)

$t_{\frac{1}{2}}$ = half life of the first order conversion = 56.6 hour

$\lambda$ = rate constant

$A=A_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}$

Now put all the given values in this formula, we get

$0.1x=x\times e^{-(\frac{0.693}{56.6 hour})\times t}$

t = 188.06 hour

It will take 188.06 hours for the concentration of A to decrease 10.0% of its original concentration.

4 0

3 years ago

Balanced nuclear equation, what two things must be conserved

In-s [12.5K]

If you only want to balance nuclear reactions, then you should know that number of nucleons are conserved before and after nuclear reaction. Also, charge is conserved as well.
Other things which are conserved in a nuclear reaction are:
Conservation of:
1. Parity
2. Spin
3. angular momentum(vector sum of intrinsic spin and orbital angular momentum)
4. linear momentum
5. Isotopic spin
6. Energy

7 0

3 years ago