All categories

2 years ago

Calculate the mass of hydrogen produced when 72 g of magnesium reacts with sulfuric acid.

Chemistry

1 answer:

Harman [31]2 years ago

8 0

Since this is a single replacement reaction, the equation for the reaction is:

$\text{Mg}+\text{H}_{2}\text{SO}_{4} \longrightarrow \text{MgSO}_{4}+\text{H}_{2}$

From this, we know that for every mole of magnesium consumed, 1 mole of hydrogen is produced.

The atomic mass of magnesium is 24.305 g/mol, so 72 grams of magnesium is 72/24.305 = 2.9623534252211 moles.

This means we need to find the mass of 2.9623534252211 moles of hydrogen.

Hydrogen has an atomic mass of 1.00794 g/mol, so doubling this to get the formula mass of of $\text{H}_{2}$ , we get 2.01588 g/mol, which his a mass of:

(2.01588)(2.9623534252211). which is about 5.97 g

You might be interested in

Cho biết độ tan của NH4Cl trong nước ở 20oC và 70oC lần lượt là 37,2 g/100 gam nước và 60,2 gam/100 g nước. Hòa tan 166,8 gam NH

Stolb23 [73]

Answer: Hợp chất CTHH 0 °C 10 °C 20 °C 30 °C 40 °C 50 °C 70 °C

Actini(III) hydroxide Ac(OH)3 0,0022

Amonia NH3 1176 900 702 565 428 333 188

Amoni azua NH4N3 16 25,3 37,1

View 42 more rows

hehe

8 0

3 years ago

How many moles of chlorine gas are in 1.2m^3 at room temperature and pressure?

marshall27 [118]

Answer:

look it up lol

Explanation:

quizlet

5 0

3 years ago

What layers are composed of metals? Choose all that apply. Inner core Outer core Mantle

svlad2 [7]

Answer:

to be honest ask your teacher

3 0

2 years ago

How many spatial orientations are available for the p sublevel

Sonja [21]

4 to 5 you are welcome

3 0

3 years ago

Wastewater discharged into a stream by a sugar refinery contains 3.40 g of sucrose (C12H22O11) per liter. A government-industry

Ipatiy [6.2K]

Answer: The pressure that must be applied to the apparatus is 0.239 atm

Explanation:

To calculate the osmotic pressure, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

or,

$\pi=i\times \frac{m_{solute}}{M_{solute}\times V_{solution}\text{ (in L)}}}\times RT$

where,

$\pi$ = osmotic pressure of the solution

i = Van't hoff factor = 1 (for non-electrolytes)

$m_{solute}$ = mass of sucrose = 3.40 g

$M_{solute}$ = molar mass of sucrose = 342.3 g/mol

$V_{solution}$ = Volume of solution = 1 L

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the solution = $20^oC=[20+273]K=293K$

Putting values in above equation, we get:

$\pi =1\times \frac{3.40g}{342.3g/mol\times 1}\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 293K\\\\\pi =0.239atm$

Hence, the pressure that must be applied to the apparatus is 0.239 atm

3 0

4 years ago