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lilavasa [31]
3 years ago
12

Can you please help me with the problem in the image below?

Mathematics
1 answer:
serg [7]3 years ago
4 0

Given data:

m∠P = m∠R and TP = SR

To prove that ΔQTP ≅ ΔQSR:

Consider ΔQTP and ΔQSR,

m∠P = m∠R (given angle)

TP = SR (given side)

m∠Q = m∠Q (common angle)

∴ ΔQTP ≅ ΔQSR (by ASA congruence rule)

Hence ΔQTP and ΔQSR are congruence triangles by Angle - Side - Angle congruence rule.

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Solve for t and find the value for t if I= 115, P=650, r=5%
Brrunno [24]
P=650
R= 5% annually= 0.05
T=1 month=1/12 year

Sl=Prt=650*0.05*1/12= $2.70
So the answer would be 2.7 or 2.70
5 0
3 years ago
A cook wants to make enough cookies for 150 students. The cookie recipe makes 1 dozen cookies. A dozen equals 12 cookies.
lesya692 [45]

Answer:

12.5

Step-by-step explanation:

150 / 12 = 12.5

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3 0
3 years ago
What is the equation of the midline of the sinusoidal function?<br> [Enter the answer in the box]
Contact [7]

Answer:

y=0

Step-by-step explanation:

We are asked to find the equation of mid-line of the given sinusoidal function.

Since the mid-line of a sinusoidal function is the line that runs between the maximum and minimum y-values of the function. We can consider it the middle y-value.

\text{Mid-line}=\frac{\text{Maximum value+Minimum value}}{2}

We can see from our given graph that the maximum value of our function is 5 and minimum value of our function is -5.

Upon substituting these values in mid-line formula we will get,

\text{Mid-line}=\frac{5+(-5)}{2}

\text{Mid-line}=\frac{5-5}{2}

\text{Mid-line}=\frac{0}{2}

\text{Mid-line}=0

Therefore, the equation of the mid-line of the given sinusoidal function is y=0.

3 0
3 years ago
3x+6+4=6×2+10lve for x
In-s [12.5K]
3x + 6 + 4 = 6 × 2 + 10
3x + 6 + 4 = 12 + 10
3x + 10 = 12 + 10
3x + 10 = 22
3x = 22 - 10
3x = 12
x = 12/3
x = 4

The answer is: x = 4.
3 0
3 years ago
Read 2 more answers
The slope of this graph is?
AURORKA [14]
The slope of the graph is -1/2 using the rise over run method it rises up one and too the left twice so it would he -1/2
3 0
3 years ago
Read 2 more answers
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