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3 years ago

Can you please help me with the problem in the image below?

Mathematics

1 answer:

serg [7]3 years ago

4 0

Given data:

m∠P = m∠R and TP = SR

To prove that ΔQTP ≅ ΔQSR:

Consider ΔQTP and ΔQSR,

m∠P = m∠R (given angle)

TP = SR (given side)

m∠Q = m∠Q (common angle)

∴ ΔQTP ≅ ΔQSR (by ASA congruence rule)

Hence ΔQTP and ΔQSR are congruence triangles by Angle - Side - Angle congruence rule.

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The cylinder and the sphere below have the same radius and the same volume. What is the height of the cylinder?

lyudmila [28]

Answer:

Height of cylinder (h) = (4/3)R

Step-by-step explanation:

Given:

Radius of cylinder (r1) = R

Height of cylinder (h) = H

Radius of sphere (r2) = R

Volume of cylinder = volume of sphere

Find:

Height of cylinder (h) = H = ?

Computation:

$Volume\ of\ cylinder = volume\ of\ sphere\\\\ \pi (r1)^2h =\frac{4}{3} \pi (r2)^3\\\\\pi (R)^2h =\frac{4}{3} \pi (R)^3\\\\ h=\frac{4}{3} (R)$

Height of cylinder (h) = (4/3)R

4 0

3 years ago

Hurry as this need to done before 11PM tonight!?!?! Give answer as a fraction. A) − 23 34 B) − 49 18 C) 11 37 D) 3 11

d1i1m1o1n [39]

I'm sorry that it's past 11pm, but if it still helps, the answer is 204/-576 which simplifies to 51/-144

8 0

3 years ago

2. What is gross income? What types of income are included in gross income?

gogolik [260]

Gross income is all a persons receipts and gains from all sources before any deductions.

8 0

3 years ago

Please help I'm confused. It's finding a function

shepuryov [24]

Easy, that is the slope from (2,f(2)) to (3,f(3))

remember that the slope between the points (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)

find f(2) and f(3)
f(2)=2²+6(2)+5=4+12+5=21
f(3)=3²+6(3)+5=9+18+5=32

so the slope from (2,21) to (3,32) is (32-21)/(3-2)=11/1=11

answer is 11

3 0

3 years ago

How do you write (10, -6) and (-2, -6) as an equation

Paraphin [41]

Answer:

y=-6

Step-by-step explanation:

Method 1:

Both the y coordinates of the points are the same and the x coordinates are distinct.

Therefore the straight line passing through the point is parallel to X-axis.

The common y coordinate is -6, therefore the line equation is y=-6.

Method 2:

We will solve it using general line equation

(y-y1)=( $\frac{y2-y1}{x2-x1}$ )(x-x1)

where (x1,y1) and (x2,y2) are the 2 points.

(y+6)=( $\frac{-6+6}{10+2}$ )(x+2)

(y+6)=0

y=-6

4 0

3 years ago