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9966 [12]
3 years ago
7

While the carbonyl stretching frequency for simple aldehydes, ketones, and carboxylic acids is about 1710 cm-1, the carbonyl str

etching frequency for acid chlorides is about ________.
A) 1800 cm-1
B) 1660 cm-1
C) 2200 cm-1
D) 1735 cm-1
E) 1700 cm-1
Chemistry
1 answer:
Virty [35]3 years ago
5 0

Answer:

A

Explanation:

Acid chloride: --C=O-Cl. Stretch range ~1750-1820cm-1. I'd probably pick

(A) 1800 cm-1, as this value is in the middle (-ish) of that range.

Hence the correct answer is 1800 cm^-1

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In science, some quantities are known as vectors. Acceleration is one type of vector. Which of the following is an example of an
galina1969 [7]

Answer: 5 m/s 2 south

Explanation:

Vector quantities have both magnitude and direction.

Scalar quantities have only magnitude.

Distance is a scalar quantity. It refers only to how far an object has traveled. For example, 4 feet is a distance; it gives no information about direction. To say an object traveled 4 feet is somewhat ambiguous. To say the object traveled 4 feet west, for example, would be a displacement, and would then be a vector quantity. It gives a more complete picture of what happened.

Mass is a scalar quantity. Simply put, it refers to how much matter an object is made up of. It has magnitude but gives no indication of direction in any sense. The vector counterpart to mass is weight.

Weight is a vector quantity. Weight is a force, and forces are vectors, i.e. having both magnitude and direction. Perceived weight of an object at rest on earth is given by

W

=

→

F

g

=

m

g

, the product of the mass of the object and the free-fall acceleration constant,

g

, or simply equal to the force of gravity acting on the object. The force of gravity acts downward.

Time is a scalar quantity (as far as we are concerned at this level). It gives information about magnitude, i.e. how much time, but no information about direction.

Volume is a scalar quantity. It refers to the amount of space that an object occupies and therefore has magnitude, but gives no information about direction.

Density is a scalar quantity, having only magnitude and giving no information about direction. We can also reason that, because density is equal to mass divided by volume and both mass and volume are scalar quantities, density must also be a scalar quantity.

Speed is a scalar quantity, having only magnitude and giving no information about direction. For example,

40

m

s

is a speed, it tells us how fast an object is traveling, but nothing abut which direction the object is traveling in. The vector counterpart to speed is velocity.

Velocity is a vector quantity. Velocities have both magnitude and direction. For example,

40

m

s

NE is a velocity.

Acceleration is a vector quantity. Acceleration has both magnitude and direction. For example,

9.8

m

s

2

downward or

−

9.8

m

s

2

vertically is an acceleration.

Force is a vector quantity. Force has both magnitude and direction. Weight is an example of force given above. Another is the force of friction, which has some magnitude and acts in the direction opposite that of motion.

Temperature is a scalar quantity. A measurement of temperature has magnitude, but gives no information about direction.

Energy is a scalar quantity. It gives information about magnitude, e.g. how much energy an object has, but none about direction.

Note that certain quantities which are alone scalars can be represented as vectors when we discuss intervals or how the quantities change (e.g. measure of increase or decrease).

6 0
3 years ago
Read 2 more answers
An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution?
umka2103 [35]

<u>Answer:</u> The boiling point of solution is 100.53

<u>Explanation:</u>

We are given:

8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

K_b = molal boiling point elevation constant = 0.51°C/m

m_{solute} = Given mass of solute (CsCl) = 8.00 g

M_{solute} = Molar mass of solute (CsCl) = 168.4  g/mol

W_{solvent} = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

\text{Boiling point of solution}-100=2\times 0.51^oC/m\times \frac{8.00\times 1000}{168.4g/mol\times 92}\\\\\text{Boiling point of solution}=100.53^oC

Hence, the boiling point of solution is 100.53

6 0
3 years ago
13. What is the molar mass of (NH4)3PO4? (Use whole number molar masses) *
Vinil7 [7]
13. C

14. 64 / 98 x 300 = 195.91 your answer is "B"
7 0
3 years ago
Calculate the molarity of a solution that contains 3.11 mol of NaNO3 dissolved in 2.50 L. Enter your answer in the provided box.
rusak2 [61]

Answer:

Molarity of a solution that contains 3.11 mol of NaNO3 is 1,24 M

Explanation:

We understand molarity as the number of moles of solute that are contained in 1 L of solution, then if in a solution of 2.50 L we have 3.11 moles, it remains to calculate how many moles do we have in 1 liter.

2,50 L .......... 3,11 moles

1 L .................. x

X = ( 1 L x 3,11 moles) / 2,50 L = 1,24

8 0
3 years ago
Suppose 10.0 mL of 2.00 MNaOH is added to (a) 0.780 L of pure water and (b) 0.780 L of a buffer solution that is 0.682 Min butan
katrin2010 [14]

Answer:

a) pH will be 12.398

b) pH will be 4.82.

Explanation:

a) The moles of NaOH added = molarity X volume (L) = 2 X 0.01 = 0.02 moles

The total volume after addition of pure water = 0.780+0.01 = 0.79 L

The new concentration of /NaOH will be:

molarity=\frac{molesofsolute}{volumeofsolution}=\frac{0.02}{0.79}=0.025M

the [OH⁻] = 0.025

pOH = -log [OH⁻] = 1.602

pH = 14 -pOH = 12.398

b) The buffer has butanoic acid and butanoate ion.

i) Before addition of NaOH the pH will be calculated using Henderson Hassalbalch's equation:

pH=pKa+log\frac{[salt]}{[acid]}

pKa=-logKa=-log(1.5X10^{-5})=4.82

ii) on addition of base the pH will increase.

8 0
4 years ago
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