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Answer:
C
Explanation:
The oxidation number of Sulphur in SO4^2- is;
x + 4(-2) = -2
x - 8 = -2
x = -2 + 8
x = 6
Now,
the oxidation number of sulphur in H2SO3 is
2 (1) + x + 3(-2) = 0
2 + x -6 = 0
-4 + x = 0
x = 4
Hence, the oxidation number of sulphur changed from +6 to +4 which signifies gain of two electrons as shown in option C.
Answer:
- nitrogen
Explanation:
SANA PO MAKATULONG PO YUNG SAGOT NA BINIGAY KO
Answer:
0.1 mol×L
Explanation:
Concentration= MOLES of SOLUTE / Volume of SOLUTION
So all we need to is to calculate the one quantity; Volume of SOLUTION has been specified to be 150 ml
So, MOLES of SOLUTE
x 100 x 10-L = ??mol; this was our starting solution.
And final CONCENTRATION=
0.15 . mol. 5 x 100 x 10-3L/
= 0.15 mol · L-1 150 x 10 3
=0.1 mol · L