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3 years ago

Combination reactions always forms what?

Chemistry

1 answer:

Arturiano [62]3 years ago

8 0

Combination reaction also called synthesis reaction, the product will always be a compound.

For example:

A + B -> AB

C2 + O2 -> CO2

H2+Cl2 -> HCl

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How do we determine the number of electrons in a neutral atom?

Elodia [21]

this is the answer of your question .

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2 years ago

The table above this place up icicle properties of a diamond by the property names have been left out of the top row which prope

Vika [28.1K]

Answer:

icicle becausit sounds right

Explanation:

icicles because it sounds right

8 0

3 years ago

According to Dalton, atoms cannot be SELECT ALL THAT APPLY a Created b Destroyed c Subdivided d Bonded

Sveta_85 [38]

Answer:

The answer is subdivided,created or destroyed

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2 years ago

calculate the volume occupied by 10g of propane gas, under normal conditions of temperature and pressure

andriy [413]

Answer:

5.5 L

Explanation:

First we convert 10 g of propane gas (C₃H₈) to moles, using its molar mass:

10 g ÷ 44 g/mol = 0.23 mol

Then we use the PV=nRT formula, where:

P = 1 atm & T = 293 K (This are normal conditions of T and P)

n = 0.23 mol

R = 0.082 atm·L·mol⁻¹·K⁻¹

V = ?

1 atm * V = 0.23 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 293 K

V = 5.5 L

3 0

2 years ago

A steel container with a movable piston contains 2.00 g of helium which was held at a constant temperature of 25 °C. Additional

shtirl [24]

Answer: D) 1.00 g

Explanation:

According to the Avogadro's law, the volume of gas is directly proportional to the number of moles of gas at same pressure and temperature. That means,

$V\propto n$

or,

$\frac{V_1}{V_2}=\frac{n_1}{n_2}$

where,

$V_1$ = initial volume of gas = 2.00 L

$V_2$ = final volume of gas = 3.00 L

$n_1$ = initial moles of gas = $\frac{\text {Given mass of helium}}{\text {molar mass of helium}}=\frac{2.00g}{4g/mol}=0.500mol$

$n_2$ = final moles of gas = ?

Now we put all the given values in this formula, we get

$\frac{2.00L}{3.00L}=\frac{0.500mol}{n_2}$

$n_2=0.75mole$

Mass of helium = $moles\times {\text {molar mass}}=0.75\times 4=3.00g$

Thus mass of helium added = (3.00-2.00) g = 1.00 g

4 0

2 years ago