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Igoryamba
3 years ago
7

A group of students auditioned for a theater performance and 3/4 of the group less six students made up the cast of 42 students.

Write an equation to represent the total number of students who auditioned, t.
Mathematics
1 answer:
LenKa [72]3 years ago
8 0

Answer:

3/4x-6=42

x=64

Step-by-step explanation:

Let the number of students be x hence 3/4 of this number will be 3/4x

Since the number was 42 if they were 3/4x less six, it means minus six hence

3/4x-6=42

Therefore, the equation will be

3/4x-6=42

Solving the equation

3/4 x=42+6=48

3/4x=48

X=62

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2 years ago
The atmospheric pressure on an object decreases as altitude increases. If a is the height (in km) above sea level, then the pres
seraphim [82]

Answer:

373.8mmHg

Step-by-step explanation:

a =height (in km) above sea level,

the pressure P(a) (in mmHg) is approximated given as

P(a) = 760e–0.13a .

To determine the atmospheric pressure at 5.458 km, then we will input into the equation

P(5.458km) = 760e–0.13a .

= 760e^(-0.13×5.458)

=760e^-(0.70954)

= 760×0.4919

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Therefore, the atmospheric pressure at 5.458 km is 373.8mmHg

3 0
2 years ago
Pranav ate pizza for dinner on Monday night and had 2/3 of the pizza left over. On Tuesday night, he ate 1/2 of what was left. H
ale4655 [162]

Answer: 1/3

Step-by-step explanation:

From the question, we are informed that Pranav ate pizza for dinner on Monday night and had 2/3 of the pizza left over. We are further told that on Tuesday night, he ate 1/2 of what was left.

The amount of pizza that Pranav ate on Tuesday will be:

= 1/2 × 2/3

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She ate 1/3 on Tuesday

6 0
2 years ago
Given two points M & N on the coordinate plane, find the slope of MN , and state the slope of the line perpendicular to MN .
telo118 [61]

Answer:

Problem 1)       m = \dfrac{1}{4}     slope_{perpendicular} = -4

Problem 2)      m = \dfrac{1}{3}     slope_{perpendicular} = -3

Step-by-step explanation:

slope = m = \dfrac{y_2 - y_1}{x_2 - x_1}

slope_{perpendicular} = \dfrac{-1}{m}

Problem 1) M(9,6), N(1,4)

slope = m = \dfrac{6 - 4}{9 - 1} = \dfrac{2}{8} = \dfrac{1}{4}

slope_{perpendicular} = \dfrac{-1}{\frac{1}{4}} = -4

Problem 2) M(-2,2), N(4,-4)

slope = m = \dfrac{4 - 2}{4 - (-2)} = \dfrac{2}{6} = \dfrac{1}{3}

slope_{perpendicular} = \dfrac{-1}{\frac{1}{3}} = -3

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2 years ago
Find the x value 7x-1+6x-1=180
Ede4ka [16]
430 but I don’t auctally know
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