Answer:
18245
Step-by-step explanation:
We have to use L.C.M,
L.C.M(20,24,32,38)
2|20,24,32,38
2| 10 ,12 ,16 ,19
2| 5 , 6 , 8 , 19
2| 5 , 3 , 4 , 19
2| 5 , 3 , 2 , 19
L.C.M = 2 x 2 x 2 x 2 x 2 x 2 x 5 x 3 x 19
= 18240
Now for each case remainder is 5,
So the number is 18240+5
=> 18245
-2
the second equation is the result of subtracting 2
Answer:
Step-by-step explanation:
each zero of the function will have a factor of (x - x₀)
h(x) = a(x + 3)(x + 2)(x - 1)
h(x) = a(x + 3)(x² + x - 2)
h(x) = a(x³ + 4x² + x - 6)
or the third option works if a = 1
however this equation gives us the points (0, -6) and (-1. -4), so "a" must be -2
h(x) = -2x³ - 8x² - 2x + 12
to fit ALL of the given points as it fits the three zeros and also h(0) and h(-1) so I guess that is why the given group is a <u><em>partial</em></u> set of solution sets
I think it would be (x+7)/7
