Answer:
Step-by-step explanation:
The answer is 10.124
If it reaches its maximum height a t=3 its velocity must be zero at t=3
dy/dx=0 at t=3
dA/dx=4x+12=24 at t=3 so this does not apply
dB/dx=-4x+12=0 at t=3 and B=13 at t=3 so B applies
dC/dx=-4x-12=-24 at t=3 so this does not apply
dD/dx=-4x-12=-24 at t=3 so this does not apply
dE/dx=-4x-12=-24 at t=3 so this does not apply
So only quadratic B: reaches a maximum height of 13 feet at 3 seconds.
The correct question is
<span>A cylinder has a volume of 320 pi in</span>³<span>. and a height of 5". Find the radius of the cylinder</span>
we know that
[volume of a cylinder]=pi*r²*h----> r²=volume/(pi*h)
r=√[volume/(pi*h)]
volume=320*pi in³
h=5 in
so
r=√[320*pi/(pi*5)]--------> r=8 in
the answer is
8 in
y=2/3y-3
1. y = 2/3 (9)-3 multiply 9 and 2 =18/3
y=18/3-3 divide 18 and 3 =6
y=6-3 subt. 3
y=3
2. -11=2/3x - 3
-11+3 = 2/3 x add 3 to both sides to cancel -3
-8=2/3 x
(3/2)-8 = (2/3)3/2 x multiply both sides by reciprical of 2/3
-24/2 = x divide
-12=x
