Answer:
Ms. Kang is incorrect because there is only one solution to that equation and that is b=5/3
Answer:
y = 3x -8
Step-by-step explanation:
I find it convenient to start with a version of the point-slope form of the equation for a line. That is, for point (h, k) and slope m, ...
y = m(x -h) +k
For your m=3 and (h, k) = (3, 1), this equation becomes ...
y = 3(x -3) +1
Eliminating parentheses puts this in the form you desire:
y = 3x -8
Answer:
Step-by-step explanation:
To solve equations like this you need to to get x by itself.
So, Let's multiply both sides by 5 to get rid of 5.
3x/5 *5 = 30 * 5
= 3x = 150
Now we divide both sides by 3 to get x by itself,
3x/3 = 150/3
x = 50
Answer:
WXYZ can not be a rectangle because consecutive sides are not perpendicular to each other.
Step-by-step explanation:
The given vertices are W(-4,3), X(1,5), Y(3,1) and Z(-2,-1).
Plot these points on coordinate plane and draw the quadrilateral as shown below.
Using this formula, we get
Now,
Here, WX and XY are two consecutive sides of quadrilateral but the product of their slopes is not equal to -1. It means they are not perpendicular to each other.
Since, all interior angles of a rectangle are right angles, therefore, WXYZ can not be a rectangle.
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
