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4 years ago

HELP Can you determine the third angle measure in a triangle, if you know the other two angles?

Mathematics

1 answer:

NNADVOKAT [17]4 years ago

8 0

Answer:

yes; you can just remember that all the angles on a triangle equal 180 so just add the two angles, subtract from 180 to get your last angle degrees.

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1. Determine whether the situation is a permutation or a combination

iVinArrow [24]

1-b cuz its describing numbers
2-A-prmation again
3-7C5 = 7!/(5!2!) = 7*6/2 = 21 so its B
4-792
5-d
hoped i helped

6 0

3 years ago

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The graphs of f(x) =-2x and g(x)=(1/2)^z are shown

ELEN [110]

Answer:

f(x)-3x+5 and g(x)=4+5 is it true ?Step-by-step explanation:

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3 years ago

Mrs. Barnes washed 2 7 of her laundry. Her son washed 1 4 of it. Who washed most of the laundry? How much of the laundry still n

wlad13 [49]

Answer:

Mrs. Barnes washed more.

Step-by-step explanation:

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3 years ago

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What is the value of x

irga5000 [103]

Answer:

X=24

Step-by-step explanation:

1. (4x + 11) + (3x + 1) = 180 (Combine like terms)

2. 7x + 12 = 180 (Subtract 12 from both sides)

3. 7x = 168 (Divide both sides by 7)

4. x = 24

3 0

4 years ago

Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.

valentina_108 [34]

Answer:

Correct answer:

A. I and II

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with $f^{-1}(x)$

Given that:

$I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3$

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = $a^{-1}(x)$ = $a(x)$ Hence, I is true.

II. $y =\dfrac{1}{x}$

Replacing y with and x with y:

$x =\dfrac{1}{y}$

$x=\dfrac{1}{a^{-1}(x)}$

$\Rightarrow a^{-1}(x) = \dfrac{1}{x}$

$a^{-1}(x)$ = $a(x)$ Hence, II is true.

III. $y =x^{2}$

Replacing y with and x with y:

$x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)$

Hence, III is not true.

IV. $y =x^{3}$

Replacing y with and x with y:

$x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)$

Hence, IV is not true.

Correct answer:

A. I and II

4 0

3 years ago