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LenaWriter [7]
3 years ago
8

4. y = -(x+2)2 - 7how do you write the equation in standard Form​

Mathematics
1 answer:
borishaifa [10]3 years ago
3 0

Answer:

2x+4y=-11

Step-by-step explanation:

4. y = -(x+2)2 - 7

4y=-2x-4-7

4y=-2x-11

2x+4y=-11

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Which one should I choose
bulgar [2K]

Answer:

I believe the answer is 12x 5

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3 years ago
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In 1980 (before the era of in-vitro fertilization), there were 3,612,258 births in the United States (according to the U.S. Cens
scoray [572]

Answer:

There was a 1.93% probability of having multiples (twins or more) in 1980.

Step-by-step explanation:

There were 3,612,258 births in the US in 1980.

Of those,

68339 + 1337 = 69676 were multiplies.

So

What was the probability of having multiples (twins or more) in 1980?

P = \frac{69676}{3612258} = 0.0193

There was a 1.93% probability of having multiples (twins or more) in 1980.

8 0
3 years ago
Describe at least two differences between constructing an inscribed regular
Naddika [18.5K]

Answer:

They are very different because hexagons are amazing and squares are boring.

Step-by-step explanation:

4 0
3 years ago
-4x + 7 is greater than or equal to 83<br> (sorry, i couldn't get the sign for it)
bezimeni [28]

Answer:

-19

Step-by-step explanation:

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then you divide it by -4 which give you -19

4 0
2 years ago
Check all of the ordered pairs that satisfy the equation below.y=2/5x
zvonat [6]

We are going to do this step by step:

Let's start with option A

A.

X = 25 and Y = 5/2

y=\frac{2}{5}\cdot x=\frac{2}{5}\cdot25=\frac{2\cdot25}{5}=\frac{50}{5}=\frac{5\cdot10}{5\cdot1}=10

In this case, when X = 25 , then Y = 10 ,which is different to 5/2

B.

X = 14 , Y = 35

y=\frac{2}{5}\cdot14=\frac{28}{5}

In case, when X = 14, then Y = 28/5, which is different to 35

C.

X = 40 , Y = 24

y=\frac{2}{5}\cdot40=\frac{80}{5}=16

Similarly, in this case, when X = 40, then Y = 16, which is different to 24

D.

X = 10 , Y=4

y=\frac{2}{5}\cdot10=\frac{20}{5}=4

Now, in this case, we can see that when X = 10, then Y = 4 which is the same as the given value of Y

E.

X = 50 , Y = 20

y=\frac{2}{5}\cdot50=\frac{100}{5}=20

In this case, the values of Y are also the same.

F.

X = 30 , Y = 12

y=\frac{2}{5}\cdot30=\frac{60}{5}=12

Again, in this case, the values of Y are the same, so the pair satisfies the equation.

In conclusion: options D, E and F satisfy the equation

3 0
1 year ago
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