How would you graph y=2x +5?
2 answers:
Answer:
STEP 1. Locate the y-intercept on the graph
- Locate 5 on the y-axis
STEP 2. Use [Rise/Run] method to graph the slope
- Since the slope is 2, [Rise/Run] will be [2/1] which means 2 unit vertically (y), 1 unit horizontally (x)
----------------------
and boom!! That's all!!
----------------------
EXTRA, this is the graph for y=2x+5
Hope this helps!! :)
Please let me know if you have any question
Answer:
Step-by-step explanation:
always start with the y-intercept which is ur b in y=mx+b
so u start with 5 on the y-axis
then since the slope is positive 2 u go up two times *FYI: put a 1 under the 2.*
up 2 and go right one time.
it should look like this:
ik this doesnt make sense but hope this helps...
You might be interested in
Step-by-step explanation:
The question isn't clear, so I'll just give you a formula to find the area of trapezoid,
(a+b)*h/2, where a = base side, b = top side, h = height.
So, let's say two sides are 3 yd and 7 yd, and height is 3 yd, so the area becomes,
(3+7)*3/2
= 10*3/2
= 30/2
= 15 yd²
Answered by GAUTHMATH
