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scoray [572]
3 years ago
9

How would you graph y=2x +5?

Mathematics
2 answers:
Tanya [424]3 years ago
6 0

Answer:

STEP 1. Locate the y-intercept on the graph

- Locate 5 on the y-axis

STEP 2. Use [Rise/Run] method to graph the slope

- Since the slope is 2, [Rise/Run] will be [2/1] which means 2 unit vertically (y), 1 unit horizontally (x)

----------------------

and boom!! That's all!!

----------------------

EXTRA, this is the graph for y=2x+5

Hope this helps!! :)

Please let me know if you have any question

Korolek [52]3 years ago
4 0

Answer:

Step-by-step explanation:

always start with the y-intercept which is ur b in y=mx+b

so u start with 5 on the y-axis

then since the slope is positive 2 u go up two times *FYI: put a 1 under the 2.*

up 2 and go right one time.

it should look like this:

ik this doesnt make sense but hope this helps...

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An HP laser printer is advertised to print text documents at a speed of 18 ppm (pages per minute). The manufacturer tells you th
anastassius [24]

Answer:

0.288

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 17.48, \sigma = 3.25, n = 10, s = \frac{3.25}{\sqrt{10}} = 1.027740

Find the probability that the mean printing speed of the sample is greater than 18.06 ppm.

This is 1 subtracted by the pvalue of Z when X = 18.06. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{18.06 - 17.48}{1.027740}

Z = 0.56

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The answer is 0.288

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Answer:

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