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diamong [38]
3 years ago
5

The mean (average) of 4 numbers is 88.

Mathematics
2 answers:
yawa3891 [41]3 years ago
7 0

Answer:

92

Step-by-step explanation:

add all the numbers and divide by 4, it is 88!

adoni [48]3 years ago
3 0
Here is your answer mate✌️

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Find the area of the figure
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Answer:

Below

Step-by-step explanation:

First I found the area of the portion that extends off (if that makes sense??)

It is a triangle, so use A = bh/2

A = (2)(6) / 2

   = 6 cm^2

Next I found the area of the rectangle using A = LW

A = (6)(3)

   = 18 cm^2

Total area = 18 + 6

                 = 24 cm^2

Hope this helps! Best of luck <3

5 0
3 years ago
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Each pound of fruit costs $4. Write an expression that shows the total cost of the fruit. Use the variable you identified in que
vovangra [49]

Answer:

$4f

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Let's assume f represents the number of pounds of fruit.

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This is $f * 4, or in a simpler form, $4f.

6 0
3 years ago
If a right triangle has a hypotenuse of 13 inches and a leg of 5 inches, how could you use the Pythagorean Theorem to find the m
zaharov [31]
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so, missing side will be 12 inches

hope it helps


Hyp^2 = Base^2 + perpendicular^2
4 0
2 years ago
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15. The table below shows the various ways
Kipish [7]

Answer:

45 %  

Step-by-step explanation:

\begin{array}{lc}\textbf{Method} & \textbf{Number}\\\text{Walk} & 36 \\\text{Bus} & 26 \\\text{Car} & 18 \\\text{TOTAL} & \mathbf{80} \\\end{array}\\\text{Percent of walkers} = \dfrac{36}{80} \times 100 \% = \mathbf{45 \, \%}

7 0
3 years ago
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You measure 20 turtles' weights, and find they have a mean weight of 45 ounces. Assume the population standard deviation is 11.5
Naily [24]

Answer: the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23

Step-by-step explanation:

Formula for margin of error : E=\dfrac{z^*\times (Population\ standard\ deviation)}{\sqrt{Sample\ size}}

, where z* = Critical z-value.

Given: population standard deviation = 11.5 ounces

Sample size = 20

Z value for 90% confidence level = 1.645

margin of error (E) = \dfrac{1.645\times11.5}{\sqrt{20}}

\approx4.23

Hence, the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23

3 0
2 years ago
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