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Alex777 [14]
4 years ago
10

Which decimal is less than 0.8 and greater than 0.02

Mathematics
2 answers:
Taya2010 [7]4 years ago
5 0

Answer:

Less than 0.8 and greater than 0.02

0.8 > a > 0,02

There are many decimals:

0.7

0.67

0.6

0.5

0.4

0.3

0.2

0.1

0.023

0.021

and many others

nikklg [1K]4 years ago
4 0

Answer:

0.02<x<0.80

0.4

Step-by-step explanation:

0.02 is equal to 2/100 and 0.8 is equal to 80/100

so you could really choose any number between 0.03 and 0.79

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Please help will mark brainliest
Ivenika [448]

Answer:

It should be -64

Step-by-step explanation:

6 0
3 years ago
What is the expansion of (3+x)^4
Vlad1618 [11]

Answer:

\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81

Step-by-step explanation:

Considering the expression

\left(3+x\right)^4

Lets determine the expansion of the expression

\left(3+x\right)^4

\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i

a=3,\:\:b=x

=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i

Expanding summation

\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}

i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0

i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1

i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2

i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3

i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4

=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4

=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4

as

\frac{4!}{0!\left(4-0\right)!}\cdot \:\:3^4x^0:\:\:\:\:\:\:81

\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1:\quad 108x

\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2:\quad 54x^2

\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3:\quad 12x^3

\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4:\quad x^4

so equation becomes

=81+108x+54x^2+12x^3+x^4

=x^4+12x^3+54x^2+108x+81

Therefore,

  • \left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81
6 0
3 years ago
Please help I'll give brainiest
Komok [63]
For the first is 3864
The second is 1320
A=3.14(which is pie) x 20.5^2
A=420x pie
A=1320
For the third is 2544
3864-1320=2544
Sorry if this is wrong too.
8 0
2 years ago
Read 2 more answers
Gisele went to the shoe store and bought two pairs of flats. One pair was $21.20, and the other was $31.50. If she has $60.00, h
Andrei [34K]
$8.30?

I need more info, is this including tax or are you having to tax the items as well?
5 0
3 years ago
Read 2 more answers
3.57 x 10 <br> write in standard form
Bess [88]

\huge\text{Hey there!}

\textsf{3.57}\times\textsf{10}^\mathsf{3}\\\\\mathsf{10^3}\\\mathsf{\rightarrow 10\times10\times10}\\\mathsf{\rightarrow100\times10}\\\mathsf{\rightarrow 1,000}\\\\\textsf{3.57}\times\textsf{1,000}\\\rightarrow\textsf{3,570}\\\rightarrow\mathsf{3.57\times10^3}\\\\\huge\boxed{Answer: {\frak{3.57\times 10^3}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

7 0
3 years ago
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