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ValentinkaMS [17]
3 years ago
10

Consider the following half reaction in which nitrate is reduced to nitrite: NO3– 2H 2e– → NO2– H2O. The reaction has a ΔG°' val

ue of –81 kJ/mol. The negative value of ΔG°' results from the very __________ E°' value of the redox couple NO3–/NO2–, and it reflects the strong tendency of nitrate to __________ electrons. Choose one:A. positive / donateB. negative/ acceptC. negative / donateD. positive / accept
Chemistry
1 answer:
drek231 [11]3 years ago
6 0

Answer:

D. positive/accept

Explanation:

a) The standard gibbs free energy (ΔG⁰) is related to the standard cell potential (E⁰) as follows:

\Delta G^{0}= -nFE^{0}-----(1)

where n = number of electrons

F = faraday constant

The given half  reaction reaction has ΔG⁰ = -81 kJ/mol. Based on equation (1) a negative value for the free energy can be obtained only if E⁰ is positive.

Thus, the negative value of ΔG°' results from the very positive value of E⁰

b) The value of E⁰ is the standard reduction potential which reflects the tendency of the system to accept electrons and get reduced. Higher (more positive) the value, greater will be the tendency to accept electrons.

Therefore, the positive E⁰ value of the redox couple NO3–/NO2– reflects the strong tendency of nitrate to <u>accept </u>electrons.

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Answer:

The answer is 54

Explanation:

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3 years ago
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so a cat and a mouse walk in to a store

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PLEAS HELP ASAP!!! Which of these statements best explains why the running costs for geothermal power plants are very low?
natima [27]
Correct answer is <span>Fuels do not have to be purchased to generate power.</span>
4 0
3 years ago
density of a piece of ebony wood is 1.174 g/ml. what is the volume in quarts of a 2.1549 lb piece of this ebony wood?
lapo4ka [179]

0.88qt

Explanation:

Given parameters:

Density of ebony wood = 1.174g/ml

Mass of wood = 2.1549lb

Unknown:

Volume of the wood in quarts = ?

Solution:

Density is defined as the mass per unit volume of a substance.

Mass is the quantity of matter the wood contains.

Volume is the space it occupies.

To solve this problem, convert the mass form pounds into grams and plug into the density equation to find volume.

Then convert the volume from mL to quarts.

 Density = \frac{mass}{volume}

 Volume = \frac{mass}{density}

    1 pound = 453.592g

   2.1549 lb =  2.1549 x 453.592 = 977.5g

Volume = \frac{977.5}{1.174} = 832.6mL

     1 quart = 946.353mL

        Therefore 832.6mL x \frac{1qt}{946.353} = 0.88qt

learn more:

Density brainly.com/question/8441651

#learnwithBrainly

7 0
4 years ago
Calculate the pKa of lactic acid (CH3CH(OH)COOH) given the following information. 3.005 grams of potassium lactate are added to
snow_lady [41]

Answer:

\displaystyle \text{p} K_a \approx 3.856

Explanation:

Because 3.005 grams of potassium lactate is added to 100. mL of solution, its concentration is:


\displaystyle \begin{aligned} \left[ \text{KC$_3$H_$_5$O$_3$}\right]  & = \frac{3.005\text{ g KC$_3$H_$_5$O$_3$}}{100.\text{ mL}} \cdot \frac{1\text{ mol KC$_3$H_$_5$O$_3$}}{128.17 \text{ g KC$_3$H_$_5$O$_3$}} \cdot \frac{1000\text{ mL}}{1\text{ L}} \\ \\ &= 0.234\text{ M}\end{aligned}

By solubility rules, potassium is completely soluble, so the compound will dissociate completely into potassium and lactate ions. Therefore, [KC₃H₅O₃] = [C₃H₅O₃⁺]. Note that lactate is the conjugate base of lactic acid.

Recall the Henderson-Hasselbalch equation:

\displaystyle \begin{aligned}\text{pH} = \text{p}K_a + \log \frac{\left[\text{Base}\right]}{\left[\text{Acid}\right]} \end{aligned}

[Base] = 0.234 M and [Acid] = 0.500 M. We are given that the resulting pH is 3.526. Substitute and solve for p<em>Kₐ</em>:

\displaystyle \begin{aligned} (3.526) & = \text{p}K_a + \log \frac{(0.234)}{(0.500)} \\ \\ 3.526 & = \text{p}K_a + (-0.330) \\ \\ \text{p}K_a & = 3.856\end{aligned}

In conclusion, the p<em>Kₐ </em>value of lactic acid is about 3.856.

5 0
2 years ago
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