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3 years ago

WILL CHOSE THE BRAINLIEST!!! NEED HELP FAST!!!

Chemistry

1 answer:

skelet666 [1.2K]3 years ago

3 0

Its not always accurate because you dont know what they could have done to it before they try to sell it

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What is a potential risk of genetically modified food?

Ivahew [28]

It would be D since it could be unhealthy for you.

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3 years ago

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The following characteristics describe which type of mixture, homogeneous or heterogeneous? The substance is mixed uniformly thr

alexira [117]

The correct answer to this question is letter "A. homogeneous mixture." The following characteristics describe the type of mixture, which is a homogeneous mixture. The substance is mixed uniformly throughout and each part of <span>the substance contains the same ratio of materials with the same properties</span>

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3 years ago

An overseas flight leaves New York in the late afternoon and arrives in London 8.50 hours later. The airline distance from New Y

Evgesh-ka [11]

Answer:

v = 658.82 km/h

Explanation:

The distance between New York and London is $5.6\times 10^3\ km$

Time taken from New York to London is 8.5 hours

We need to find the average speed of the plane.

Total distance covered divided by the total time taken is equal to the average speed of an object. So,

$v=\dfrac{d}{t}\\\\v=\dfrac{5.6\times 10^3\ km}{8.5\ h}\\\\v=658.82\ km/h$

So, the average speed of the plane is 658.82 km/h.

4 0

3 years ago

He rate constant of a reaction is 4.55 × 10−5 l/mol·s at 195°c and 8.75 × 10−3 l/mol·s at 258°c. what is the activation energy o

Xelga [282]

Answer : The activation energy of the reaction is, $17.285\times 10^4kJ/mole$

Solution :

The relation between the rate constant the activation energy is,

$\log \frac{K_2}{K_1}=\frac{Ea}{2.303\times R}\times [\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = initial rate constant = $4.55\times 10^{-5}L/mole\text{ s}$

$K_2$ = final rate constant = $8.75\times 10^{-3}L/mole\text{ s}$

$T_1$ = initial temperature = $195^oC=273+195=468K$

$T_2$ = final temperature = $258^oC=273+258=531K$

R = gas constant = 8.314 kJ/moleK

Ea = activation energy

Now put all the given values in the above formula, we get the activation energy.

$\log \frac{8.75\times 10^{-3}L/mole\text{ s}}{4.55\times 10^{-5}L/mole\text{ s}}=\frac{Ea}{2.303\times (8.314kJ/moleK)}\times [\frac{1}{468K}-\frac{1}{531K}]$