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Inessa05 [86]
3 years ago
7

When titrating a strong monoprotic acid and koh at 25°c, the ph will be less than 7 at the equivalence point. ph will be greater

than 7 at the equivalence point. titration will require more moles of base than acid to reach the equivalence point. ph will be equal to 7 at the equivalence point. titration will require more moles of acid than base to reach the equivalence point?
Chemistry
1 answer:
iVinArrow [24]3 years ago
8 0
By definition titraion of a monoprotic acid with means that the equivalence point implies netrality of the solution, which is pH = 7.

So, the answer is that pH will be equal to 7 at the equivalence.

Given that the acid is monoprotic and KOH has one OH- radical per molecule of KOH, the titration will require the same number of moles of acid than base to reach the equivalence point, as you can see in this equation, representing the monoprotic acid as HA:

 HA + KOH = K(+) + A(-) + H2O => 1 mol HA per 1 mol KOH.
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<h3>How to calculate moles of a substance?</h3>

The moles of a compound can be calculated from:

\rm Moles=\dfrac{Mass}{Molar\;mass}

The molarity can be defined as the moles of solute in a liter of solution.

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The moles of potassium nitrate in 2 M, 500 mL solution are 1 mol.

Learn more about moles, here:

brainly.com/question/15209553

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Read 2 more answers
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