Let us say T= probability of head turning up = 1/2 in one toss
H = probability of a tail turning up = 1/2 in one toss
Then P (56 heads or more) =
1/2^100 [ C(100,56) + C(100,57) + C(100,58) + ....
C(100,98) + C(100,99) + C(100,100) ]
where C(N, R) = N ! / [ (N - R)! R! ] number of occurrances of R formed from
N tosses.
Answer:
8.3
Step-by-step explanation:
hopeee this helpss outt !!
<span>First of all, we need to put commas in the number so it would look less confusing
309 , 099 , 990
Hundred million hundred of thousnd Hundred
So the correct way to say it would be : three hundred nine million ninety nine thousand nine hundred and ninetyHope this helps. Let me know if you need additional help!</span>
Answer: Never true.
Step-by-step explanation: Distribute the numbers: 4 times x is 4x, 4 times 3 is 12. Then you have the equation: -x+4x +12 = -12. Now, choose a random number, maybe -4. A negative plus a negative cancels out so you are left with 4-16(Because you distribute the number) +12 = -12. 4-16 is -12. -12 plus 12 equals 0.
