I need help on this one

Jerome used 3 and 1/4 gallons of gasoline while driving from school to to his baseball game. If he originally had 7 gallons in h

kozerog [31]

7 - 3 1/4 = (turn mixed number to improper fraction
7 - 13/4 = (common denominator is 4)
28/4 - 13/4 =
15/4 or 3 3/4 gallons remain in the tank

6 0

2 years ago

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In Mr. Dixon's math class, 7 out of 20 students are in the math club. What percent of the students are in the math club?

Ganezh [65]

7/20 = 0.35
35 percent.

5 0

2 years ago

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£70 is divided between Natasha, Richard & Stephen so that Natasha gets twice as much as Richard, and Richard gets three time

Korvikt [17]

The share of Natasha is £ 42

<em><u>Solution:</u></em>

£70 is divided between Natasha, Richard & Stephen

Total amount = 70

Let the share of natasha be "x"

Let the share of richard be "y"

Let the share of stephen be "z"

Natasha gets twice as much as Richard

x = 2y ------ eqn 1

Richard gets three times as much as Stephen

y = 3z

$z = \frac{y}{3}$ ----- eqn 2

Total amount = 70

share of natasha + share of richard + share of stephen = 70

x + y + z = 70

Substitute eqn 1 and eqn 2

$2y + y + \frac{y}{3} = 70\\\\\frac{6y+3y+y}{3} = 70\\\\10y = 210\\\\y = 21$

Substitute y = 21 in eqn 1

x = 2y = 2(21) = 42

x = 42

Thus natasha gets £ 42

6 0

2 years ago

Please help me hurry please

aalyn [17]

Answer:

y = root under 24 (evaluate it if necessary)

or y = 2 root 6

Step-by-step explanation:

Let the reference angle be x

for the triangle in left,

b = 6-4 = 2

Now,

taking x as refrence angle,

cosx = b/h

or, cosx = 2/h

again,

for the bigger triangle,

taking x as reference angle,

cosx = b/h

or, cosx = b/6

As we can see base of bigger triangle is equal to hypotenuse of triangle at the left,

Let's suppose its a

so, cosx = a/6 = 2/a

now,

a/6 = 2/a

or, a² = 12

now,

for bigger triangle, using pythagoras theorem,

h² = p²+b²

or, 6² = y² + a²

or, 36 = y² + 12

or, y² = 24

so, y = root under 24

5 0

1 year ago

If a test of H subscript 0 colon space mu subscript D equals 0 space v s. space H subscript a colon space space mu subscript D g

lara [203]

Answer:

$p_v =P(t_{(n-1)}>t_{calculated}) =0.0601$

The p value on this case is given by the problem.

If we compare the p value with a significance level assumed $\alpha=0.05$ , we see that $p_v > \alpha$ and we can conclude that we FAIL to reject the null hypothesis that the difference mean between after and before is less or equal than 0.

Step-by-step explanation:

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.

Let put some notation

x=test value before , y = test value after

The system of hypothesis for this case are:

Null hypothesis: $\mu_y- \mu_x \leq 0$

Alternative hypothesis: $\mu_y -\mu_x >0$

The first step is calculate the difference $d_i=y_i-x_i$

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}$

The 4 step is calculate the statistic given by :

$t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=t_{calculated}$

The next step is calculate the degrees of freedom given by:

$df=n-1$

Now we can calculate the p value, since we have a right tailed test the p value is given by:

$p_v =P(t_{(n-1)}>t_{calculated}) =0.0601$

The p value on this case is given by the problem.

If we compare the p value with a significance level assumed $\alpha=0.05$ , we see that $p_v > \alpha$ and we can conclude that we FAIL to reject the null hypothesis that the difference mean between after and before is less or equal than 0.

4 0

3 years ago