If we need our line to pass through point C, then we have to use the x and coordinates of point C in our new equation. If that line is to be perpendicular to AB, we also need to find the slope of AB and then take its opposite reciprocal. First things first. Point C lies at (6, 4) so we will use x = 6 and y = 4 in our equation in a bit. The coordinates of A are (-2, 4) and the coordinates of B are (2, -8) so the slope between them is
which is -3. The opposite reciprocal of -3 is 1/3. That's the slope we will use along with the points from C to write the new equation. We will do this by plugging in x, y, and m (slope) into the slope-intercept form of a line and solve for b.
and 4 = 2 + b. So b = 2. That's the y-intercept, the point on the y axis where the line goes through when x is 0. Therefore, the point you're looking for is (0, 2).
Revenue = Sales Volume (x) times Price. Price depends on volume sold: the more you are willing to sell per week, the lower your average price will have to be to get them all sold.
<span>eg, if there are a fixed number of buyers with a variety of incomes, then you might be able to sell the first 10 per month for £30 each through the up-market High Street jeweller. If you want to sell an extra 10 per month you might have to reduce the price to £15 and sell them through Asda/WalMart. And to move another 10 per month you may have to sell them from a street stall at £5 each! </span>
Answer:
26.8°
Step-by-step explanation:
You find the supplementary angle by 180° - 153.2° = 26.8°
Answer:
2 stalls
Step-by-step explanation:
Mr. Hayes has 11 straw bundles to use forr bedding in his horse stalls. What is the greatest number of stalls he can fill if each stall holds exactly 4 bundles
1 stall = 4 bundles
4 bundles = 1 stall
11 bundles = x
Cross Multiply
4x = 11
x = 11/4
x = 2 3/4 stalls
The greatest number of stalls he can build is 2 stalls
