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zimovet [89]
3 years ago
7

Solve 3 (x+4) = 3 help solve this equation

Mathematics
1 answer:
Dmitry [639]3 years ago
5 0

Answer:

x=-3

You multiply what's in parentheses by 3 and to get x by itself you have to subtract 12 from that side which leaves you with 3x= -9. You then divide by 3 to get x=-3. To check this you fill -3 into the equation and you get the correct answer, 3.

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Please help [99 points]
Luda [366]
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5 0
3 years ago
Read 2 more answers
In 14 the perimeter of the figure Is given. find the length of the indicated side
olga2289 [7]

3x - 7

The perimeter is the sum of all 3 sides of the triangle

To find the third side subtract the sum of the 2 known sides from the perimeter

x + 3 + 2x + 4 = 3x + 7

third side = 6x - (3x + 7 ) = 6x - 3x - 7 = 3x - 7


4 0
3 years ago
The perimeter of a rectangular swimming pool is 446 centimeters. The width of the pool is 7 centimeters less than the length of
Akimi4 [234]

Answer:

length = 115 cm

width = 108 cm

Step-by-step explanation:

The perimeter of a rectangular swimming pool is 446 centimeters

LEt L be the length of the pool

The width of the pool is 7 centimeters less than the length of the pool.

width = length - 7

W= L-7

Given perimeter = 446

Perimeter of rectangle = 2(length)+2(width)

446 = 2(L) + 2(W)                    we know W = L-7

446 = 2(L) + 2(L-7)    

446 = 2L + 2L - 14

Add 14 on both sides

460 = 4L

divide by 4 on both sides

L= 115

Length L= 115

Width W = L - 7 = 115 - 7= 108



5 0
3 years ago
6,7,8 what are the inequality’s
yan [13]

Answer:

Its an equation, not an inequality

3 0
3 years ago
John and Martha are contemplating having children, but John’s brother has galactosemia (an autosomal recessive disease) and Mart
Rina8888 [55]
<h2>Answer:</h2>

Probability=\frac{1}{24}

<h2>Step-by-step explanation:</h2>

As the question states,

John's brother has Galactosemia which states that his parents were both the carriers.

Therefore, the chances for the John to have the disease is = 2/3

Now,

Martha's great-grandmother also had the disease that means her children definitely carried the disease means probability of 1.

Now, one of those children married with a person.

So,

Probability for the child to have disease will be = 1/2

Now, again the child's child (Martha) probability for having the disease is = 1/2.

Therefore,

<u>The total probability for Martha's first child to be diagnosed with Galactosemia will be,</u>

Probability=\frac{2}{3}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{4}\\Probability=\frac{1}{24}

(Here, we assumed that the child has the disease therefore, the probability was taken to be = 1/4.)

<em><u>Hence, the probability for the first child to have Galactosemia is \frac{1}{24}</u></em>

3 0
3 years ago
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