Answer:
The area inside the running track is 248.5 m².
Step-by-step explanation:
The area inside the running track is given by the sum of the area of a rectangle and the area of a semicircle:
Where:
x: is one side of the rectangle = 30 m
r: is the radius = half of the other side of the rectangle = 7/2 m = 3.5 m
Hence, the total area is:
Therefore, the area inside the running track is 248.5 m².
I hope it helps you!
Answer:
∠G = 23.3
∠H = 42.8
∠J = 19.9
Step-by-step explanation:
<em>Tan(G) = 0.43</em>
=> G = Tan⁻¹(0.43)
=> <u>∠G = 23.3</u>
<em>Sin(H) = 0.68</em>
=> H = Sin⁻¹(0.68)
=> <u>∠H = 42.8</u>
<em>Cos(J) = 0.94 </em>
=> J = Cos⁻¹(0.94)
=> <u>∠J = 19.9</u>
Hope this helps!
Answer:
B) one 90 degree angle
Step-by-step explanation:
9514 1404 393
Answer:
D, F
Step-by-step explanation:
The mnemonic SOH CAH TOA can help you with this. It reminds you ...
Sin = Opposite/Hypotenus
sin(40°) = x/b . . . . matches D
Cos = Adjacent/Hypotenuse
<em> cos(40°) = a/b . . . . no match</em>
Tan = Opposite/Adjacent
tan(40°) = x/a . . . . matches F
Answer:
John ski down the mountain is 1285.37 feet.
Step-by-step explanation:
Given : John is skiing on a mountain with an altitude of 1200 feet. The angle of depression is 21.
To find : About how far does John ski down the mountain ?
Solution :
We draw a rough image of the question for easier understanding.
Refer the attached figure below.
According to question,
Let AB be the height of mountain i.e. AB=1200 feet
The angle of depression is 21 i.e. 
We have to find how far does John ski down the mountain i.e. AC = ?
Using trigonometric,




Therefore, John ski down the mountain is 1285.37 feet.