A reaction in which two ions switch places is called double-displacement reaction.
Explanation:
Double displacement reaction usually takes place between two positive ions or two negative ions. When anions or cations of totally different compounds change places, two totally different compounds are formed.
<u>Syntax for double displacement reaction:
</u>
AB + CD --> AD + BC
It can also be defined in simple terms as the reaction in which exchange of ions takes place is called double displacement reaction.
The chemical reaction is as follows:
NaOH(aq) + HCl(aq) --> NaCl(aq) + H2O (l)
Angular Velocity is the answer
You have to use the equation ΔG=ΔH-TΔS.
With that equation you know that a reaction with a positive change in enthalpy and positive change in entropy will only be spontaneous at high temperatures since ΔG needs to be negative for a reaction to be spontaneous.
I hopet this helps. Let me know if anything is unclear.
The number of mole of O₂ produced from the decomposition of H₂O₂ is 0.0033 mole
<h3>How to determine the number of mole of O₂ produced</h3>
We'll begin by obtaining the mole of H₂O₂ that decomposed. This is obatined as follow:
- Pressure (P) = 0.978 atm
- Temperature (T) = 27 °C = 27 + 273 = 300 K
- Volume (V) = 0.082 L
- Gas constant (R) = 0.0821 atm.L/Kmol
- Mole of H₂O₂ (n) =?
PV = nRT
Divide both sides by RT
n = PV / RT
n = (0.978 × 0.082) / (0.0821 × 300)
n = 0.0033 mole
Finally, we shall determine the number of mole of O₂ produced. This is illustrated below
H₂O₂ -> H₂ + O₂
From the balanced equation above,
1 mole of H₂O₂ decomposed to produce 1 moles of O₂
Therefore,
0.0033 mole of H₂O₂ will also decompose to produce = 0.0033 mole of O₂
Thus, number of mole of O₂ produced from the reaction is 0.0033 mole
Learn more about number of mole:
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Answer:
131.2 mL would be the total volume in the graduated cylinder.
Explanation:
Let's work with the density of metal to find out its volume
Metal density = Metal mass / metal volume
4.46 g/mL = 22.25 g / metal volume
Metal volume = 22.25 g / 4.46 g/mL = 4.98 mL
If we suppose aditive volume, total volume in the graduated cylinder will be:
126.3mL + 4.9mL = 131.2 mL
