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4 years ago

A eudiometer contains a 65.0 ml sample of a gas collected

Chemistry

1 answer:

SCORPION-xisa [38]4 years ago

6 0

Answer:

53.1 mL

Explanation:

Let's assume an ideal gas, and at the Standard Temperature and Pressure are equal to 273 K and 101.325 kPa.

For the ideal gas law:

P1*V1/T1 = P2*V2/T2

Where P is the pressure, V is the volume, T is temperature, 1 is the initial state and 2 the final state.

At the eudiometer, there is a mixture between the gas and the water vapor, thus, the total pressure is the sum of the partial pressure of the components. The pressure of the gas is:

P1 = 92.5 - 2.8 = 89.7 kPa

T1 = 23°C + 273 = 296 K

89.7*65/296 = 101.325*V2/273

101.325V2 = 5377.45

V2 = 53.1 mL

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<h3>Answer:</h3>

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<h3>Explanation:</h3>

<u>We are given;</u>

Initial pressure, P1 as 808 kPa
Initial temperature, T1 as 585 K
Initial volume, V1 as 295 m³
New pressure, P2 as 102 kPa
New temperature, T2 as 293 K

We are required to find the new volume;

We are going to use the combined gas law
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Answer:

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