An intensive property is the physical characteristics that have an independent magnitude. The thermometer can be used to measure the temperature. Thus, option C is correct.
<h3>What is an intensive property?</h3>
An intensive property has been constituted of the parameters that are not dependent on the size and the mass of the sample. Density, pressure, and temperature are some intensive properties.
The first image shows a weighing balance, the second shows a volumetric cylinder, and the fourth shows a ruler used to measure mass, volume, and length respectively, which are extensive properties.
Therefore, option C. thermometer measures temperature, which is an intensive property.
Learn more about the intensive property here:
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Answer:
Explanation:
Given
485 L
Required
Determine the measurement not equal to 485L
<em>From standard unit of conversion;</em>
1 KL = 1000 L
<em>Multiply both sides by 485</em>
<em>Divide both sides by 1000</em>
---- This is equivalent
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<em>From standard unit of conversion;</em>
1000 mL = 1 L
<em>Multiply both sides by 485</em>
Convert to standard form
Hence; is not equivalent to 485L
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<em>From standard unit of conversion;</em>
100 cL = 1 L
<em>Multiply both sides by 485</em>
Convert to standard form
---- This is equivalent
---------------------------------------------------------------------------------------------
μL
<em>From standard unit of conversion;</em>
1000000 μL = 1 L
<em>Multiply both sides by 485</em>
Convert to standard form
---- This is equivalent
From the list of given options;
is not equivalent to 485L
If P=M*V than P=30kg*5m/s. P=150.
P=momentum
M=mass
V=Velocity
Now the last time i have done physics was last year. but i'm pretty confident in this answer. Hope this helps!
The tea was no longer hot or (brewed) so the 5th didn’t dissolve like the others because the tea was hot or warm enough anymore it cooled down. So the sugar won’t dissolve no more.
Answer:
1.45 x 10⁻² g CO₂
Explanation:
To find the mass of carbon dioxide, you need to (1) convert grams CH₄ to moles CH₄ (via molar mass), then (2) convert moles CH₄ to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass). The final answer should have 3 sig figs to reflect the given value (5.30 x 10⁻³ g).
Molar Mass (CH₄): 12.011 g/mol + 4(1.008 g/mol)
Molar Mass (CH₄): 16.043 g/mol
Combustion of Methane:
1 CH₄ + 2 O₂ ---> 2 H₂O + 1 CO₂
Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)
Molar Mass (CO₂): 44.007 g/mol
5.30 x 10⁻³ g CH₄ 1 mole 1 mole CO₂ 44.007 g
--------------------------- x ---------------- x --------------------- x ----------------- =
16.043 g 1 mole CH₄ 1 mole
= 0.0145 g CO₂
= 1.45 x 10⁻² g CO₂
