The bond is highly polar is the scientific claim about the bond in the molecular compound HF is most likely to be true.
The term polar means that there is separation of charges, the bonds will be the more polar the greater the difference in electronegativity between the bonded atoms.
- In hydrogen fluoride, for example, F is more electronegative than H because its nucleus, with 9 positive charges, attracts e-shares with H more strongly than the nucleus of H, with only one positive charge.
- Therefore, the e- shared by covalence will be closer to F than to H and the molecule forms a permanent dipole.
Therefore, we can conclude that the bond is highly polar is the scientific claim about the bond in the molecular compound HF is most likely to be true.
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Answer:
0.013 mole
Explanation:
Step 1:
Data obtained from the question. This includes:
Volume (V) = 250 mL
Pressure (P) = 1.3 atm
Temperature (T) = 33°C
Number of mole of (n) =?
Step 2:
Conversion to appropriate units.
The volume and the temperature given in the question must be converted to their appropriate unit in order to obtain the answer to the question in the right unit.
For volume:
We must, convert mL to L
1000 mL = 1 L
Therefore, 250 mL = 250/1000 = 0.25 L
For temperature:
We, must convert °C to K.
K = °C + 273
K = 33°C + 273
K = 306K
Step 3:
Determination of the number of mole of CO2.
Applying the ideal gas equation:
PV = nRT
The number of mole of CO2 can be obtained as follow:
V = 0.25 L
P = 1.3 atm
T = 306K
R (gas constant) = 0.082atm.L/Kmol
Number of mole of (n) =?
PV = nRT
1.3 x 0.25 = n x 0.082 x 306
Divide both side by 0.082 x 306
n = (1.3 x 0.25) /(0.082 x 306)
n = 0.013 mole
Step 1 : Convert mass of Iron to moles using n = m/MM.
n(Fe) = 37.5 ÷ 55.845 = 0.671501... mol
Step 2 : Using stoichiometric ratios, find how many moles of Fe2O3 are produced.
Fe : Fe2O3 is 4:2, or simply 2:1. For every 2 moles of Fe there is Fe2O3.
Therefore, moles of Fe2O3 is half the amount of Fe!
n(Fe2O3) = 0.5 x 0.671501... = 0.33575... mol
Step 3: Convert the moles of Fe2CO3 to mass using m = n x MM.
m(Fe2O3) = 0.33575... x [2(55.845)+3(15.999)] = 53.61502... grams
Final step: round your answer to the lowest signficant figures. Since you gave me the mass of iron to 3s.f, m(Fe2O3) = <u><em>53.6 grams</em></u> (3s.f) !
Let me know if you're confused in any way!