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almond37 [142]
3 years ago
12

Part C Number of molecules in 8.437x10-2 mol C6H6

Chemistry
1 answer:
N76 [4]3 years ago
5 0

Answer:

There are 5.08\times 10^{22}\ \text{molecules of}\ C_6H_6  

Explanation:

In this problem, we need to find the number of molecules in 8.437\times 10^{-2} mol of C_6H_6.

The molar mass of C_6H_6 is 6\times 12+1\times 6=78\ g/mol

No of moles = mass/molar mass

We can find mass from above formula.

m=n\times M\\\\m=8.437\times 10^{-2}\ mol\times 78\ g/mol\\\\m=6.58\ g

Also,

No of moles = no of molecules/Avogadro number

N=n\times N_A\\\\N=8.437\times 10^{-2}\times 6.023\times 10^{23}\\\\N=5.08\times 10^{22}\ \text{molecules}

Hence, there are 5.08\times 10^{22}\ \text{molecules of}\ C_6H_6  

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Answer:

383.90K

Explanation:

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T2 = ?

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To solve for P2, we have to use pressure law which states that the pressure of a fixed mass of fixed is directly proportional to its temperature provided that volume remains constant

Mathematically,

P = kT, k = P/T

P1 / T1 = P2 / T2 = P3 / T3 =.......=Pn / Tn

P1 / T1 = P2 / T2

T2 = (P2 × T1) / P1

T2 = (990 × 330) / 851

T2 = 383.90K

The final temperature of the gas is 383.90K

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4 years ago
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<u>Answer: </u>The correct statement is X is the effective nuclear charge, and it increases across a period.

<u>Explanation:</u>

We are given that:

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The formula used for the calculation of effective nuclear charge given by Slater is:

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Hence, the correct answer is X is the effective nuclear charge, and it increases across a period.

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