Question

What are the zeros of the quadratic function f(x)=8x^2-16x-15

Answer 1

Step-by-step explanation:

Step 1:  Use the quadratic formula to find the zeros

$x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-16)\pm \sqrt{(-16)^2-4(8)(-15)} }{2(8)}$

$x=\frac{16\pm \sqrt{736} }{16}$

$x=\frac{16\pm 4\sqrt{46} }{16}$

$x=\frac{4\pm \sqrt{46} }{4}$

Answer:  $x=\frac{4\pm \sqrt{46} }{4}$