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4 years ago

When the terminal side of angle ? in standard position intersects a unit circle at (0.777, 0.629), what is cos ??

Mathematics

1 answer:

kenny6666 [7]4 years ago

5 0

Answer:

0.777

Step-by-step explanation:

The cosine is the x-coordinate of the point of intersection of the terminal ray with the unit circle.

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Jobisdone [24]

Answer:

Small number = 19

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Step-by-step explanation:

x + 3x + 14 = 90

4x + 14 = 90

4x = 90 - 14

x = 76 / 4 = 19

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3 years ago

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Anvisha [2.4K]

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3 years ago

Two vertical poles of lengths 11 ft and 14 ft stand 16 ft apart. A cable reaches from the top of one pole to some point on the g

Alex17521 [72]

We are given

total length of cable is 30 feet

and this cable is on hypotenuse sides of the triangles

so, we can draw triangle as

Let's assume those hypotenuse as 'a' and 'b'

so, we will have

$a+b=30$

now, we can find 'a' and 'b' from triangle

Smaller triangle:

$a=\sqrt{x^2+11^2}$

Larger triangle:

$b=\sqrt{(16-x)^2+14^2}$

we know that

$a+b=30$

so, we can plug this value

and we get

$\sqrt{x^2+11^2}+\sqrt{(16-x)^2+14^2} =30$

now, we can solve for x

$\left(\sqrt{x^2+11^2}\right)^2=\left(30-\sqrt{\left(16-x\right)^2+14^2}\right)^2$

$32x-1231=-60\sqrt{x^2-32x+452}$

$1024x^2-78784x+1515361=3600x^2-115200x+1627200$

now, we can use quadratic formula

we get

$x=\frac{-\sqrt{36416^2-1152389056}+36416}{5152},\:x=\frac{\sqrt{36416^2-1152389056}+36416}{5152}$

$x=4.510,x=9.627$

so,

The point should be located 4.510 feet , 9.627 feet from the smaller pole to use 30 feet cable............Answer

6 0

3 years ago

Answer fast, please!!

Vlad1618 [11]

The answer is B!!!!

3 0

3 years ago