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lukranit [14]
3 years ago
13

All statements have counterexamples. True False

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
6 0

Answer:

False

Step-by-step explanation:

Not all statements have counter examples

Artemon [7]3 years ago
4 0
If the probability that an event will occur is 0, then the event is impossible to occur
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Which expression is equivalent to 64y18 – 1000z6?
const2013 [10]
(16y6)3 - (10z2)3 I think is the right answer
3 0
3 years ago
Read 2 more answers
Which graph represents a function?
MissTica
The second to last one, looks like a really tall speed bump
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3 years ago
Thomas and Pablo began arguing about who did better on their tests, but they couldn't decide who did better given that they took
Shkiper50 [21]

It should be noted that the z score for Thomas test grade is 0.237.

<h3>How to illustrate the information?</h3>

From the information, Thomas took a test in Social Studies and earned a 74.8 and there is the fact that all the students' test grades in the Social Studies class had a mean of 72.6 and a standard deviation of 9.3,

Therefore, the z score for Thomas test grade will be:

= Test score - Mean / Standard deviation

= 74.8 - 72.6 / 9.3

= 0.237.

Therefore, it should be noted that the z score for Thomas test grade is 0.237.

Learn more about standard deviation on:

brainly.com/question/12402189

#SPJ1

Thomas and Pablo began arguing about who did better on their tests, but they couldn't decide who did better given that they took different tests. Thomas took a test in Social Studies and earned a 74.8, and Pablo took a test in Science and earned a 64.1. Use the fact that all the students' test grades in the Social Studies class had a mean of 72.6 and a standard deviation of 9.3, and all the students' test grades in Science had a mean of 61.1 and a standard deviation of 9.8 to answer the following questions.

Calculate the z score for Thomas test grade.

4 0
1 year ago
PLEASE HELP
alexgriva [62]

Answer:

Step-by-step explanation:

90.25$

5 0
1 year ago
A box has five items, three good and two defective. three items are selected at random without replacement. let x be the number
user100 [1]
This problem can be solved from first principles, case by case.  However, it can be solved systematically using the hypergeometric distribution, based on the characteristics of the problem:
- known number of defective and non-defective items.
- no replacement
- known number of items selected.

Let
a=number of defective items selected
A=total number of defective items
b=number of non-defective items selected
B=total number of non-defective items
Then 
P(a,b)=C(A,a)C(B,b)/C(A+B,a+b)
where 
C(n,r)=combination of r items selected from n,
A+B=total number of items
a+b=number of items selected

Given:
A=2
B=3
a+b=3
PMF:
P(0,3)=C(2,0)C(3,3)/C(5,3)=1*1/10=1/10
P(1,2)=C(2,1)C(3,2)/C(5,3)=2*3/10=6/10
P(2,0)=C(2,2)C(3,1)/C(5,3)=1*3/10=3/10
Check: (1+6+3)/10=1 ok
note: there are only two defectives, so the possible values of x are {0,1,2}

Therefore the 
PMF:
{(0, 0.1),(1, 0.6),(2, 0.3)}

7 0
3 years ago
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