The answer is 1761 1/2 (1761.5 in decimal form)
Answer:
Probability that the sample mean comprehensive strength exceeds 4985 psi is 0.99999.
Step-by-step explanation:
We are given that a random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength μ = 5500 psi and the standard deviation is σ = 100 psi.
<u><em>Let </em></u>
<u><em> = sample mean comprehensive strength</em></u>
The z-score probability distribution for sample mean is given by;
Z =
~ N(0,1)
where,
= population mean comprehensive strength = 5500 psi
= standard deviation = 100 psi
The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.
Now, Probability that the sample mean comprehensive strength exceeds 4985 psi is given by = P(
> 4985 psi)
P(
> 4985 psi) = P(
>
) = P(Z > -15.45) = P(Z < 15.45)
= <u>0.99999</u>
<em>Since in the z table the highest critical value of x for which a probability area is given is x = 4.40 which is 0.99999, so we assume that our required probability will be equal to 0.99999.</em>
The answer is 30°.
Rule: All three sides must add up to 180°.
Since A=60 and the side vertical to the angle which is 90° then side C would be C=90° and that adds up to 150°, so you can conclude that angle B is 30°.
I hope I helped!
let's notice the tickmarks on the left and right sides, meaning those two sides are twins, and therefore equal, so the perimeter is simply 2.5+2.5+3.5+2.5 = 11 ft.
the trapezoid has an altitude/height of 2 ft, thus
![\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=2.5\\ b=3.5\\ h=2 \end{cases}\implies A=\cfrac{2(2.5+3.5)}{2}\implies A=6](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20a%2Cb%3D%5Cstackrel%7Bbases%7D%7Bparallel~sides%7D%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D2.5%5C%5C%20b%3D3.5%5C%5C%20h%3D2%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B2%282.5%2B3.5%29%7D%7B2%7D%5Cimplies%20A%3D6)
No, because then she would have to pay 21 dollars as a total and she only has 20.
Add adult plus Child,
5.75 + 11.25 = 17
add that to the book's price,
17+3.99= 2.99
it will exceed the budget by 99 cents.