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SOVA2 [1]
4 years ago
14

(e) The number of bees spotted in Amelie's garden can also be modeled by the function B(x) = 50√ k + 2x where x is the daily hig

h temperature, in degrees Fahrenheit, and k is a positive constant. When the number of bees spotted is 100, the daily high temperature is increasing at a rate of 2 ◦F per day. According to this model, how quickly is the number of bees changing with respect to time when 100 bees are spotted?
Mathematics
1 answer:
Lunna [17]4 years ago
4 0

Answer:

\frac{dB}{dt}=4

Step-by-step explanation:

Derivative indicates rate of change of dependent variable with respect to independent variables. It indicates the slope of a line that is tangent to the curve at the specific point.

Given:

Number of bees is modeled by the function B(x)=50\sqrt{k}+2x

The daily high temperature is increasing at a rate of 2 °F per day when  the number of bees spotted is 100.

To find:

rate of change of number of bees when 100 bees are spotted

Solution:

B(x)=50\sqrt{k}+2x

Differentiate with respect to t,

\frac{dB}{dt}=0+2(\frac{dx}{dt}) \\\frac{dB}{dt}=2(\frac{dx}{dt}) \\

Put (\frac{dx}{dt}) =2

\frac{dB}{dt}=2(2)=4

At x = 100, \frac{dB}{dt}=4

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gavmur [86]

Answer:

1. 1/4+1/4=2/4=1/2

2. Yes

3. i don't know

4. Yes

Step-by-step explanation:

1. 1+1=2 therefore you get 2/4 or 1/2

2. 2/3 is the reduced form of 4/6

3. i honestly dont know

4. 3/4 is the reduced form of 9/12

5 0
3 years ago
Determine whether the following statement regarding the hypothesistest for two population proportions is true or false.
murzikaleks [220]

Answer:

False

Step-by-step explanation:

Let p1 be the population proportion for the first population

and p2 be the population proportion for the second population

Then

H_{0} p1  = p2

H_{a} p1 ≠ p2

Test statistic can be found usin the equation:

z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample population proportion for the first population
  • p2 is the sample population proportion for the second population
  • p is the pool proportion of p1 and p2
  • n1 is the sample size of the first population
  • n2 is the sample size of the second population.

As |p1-p2| gets smaller, the value of the <em>test statistic</em> gets smaller. Thus the probability of its being extreme gets smaller. This means its p-value gets higher.

As the<em> p-value</em> gets higher, the null hypothesis is less likely be rejected.

7 0
3 years ago
Which set of ordered pairs is not a direct variation?
Nina [5.8K]

Answer:

The first option is not a direct variation

Step-by-step explanation:

When we talk of a direct variation, as one value increases, the other value increases too

Or as one value decreases, the other value decreases

A direct variation is of the form;

y = kx

k = y/x

where k is the coefficient of variation that must be a constant value all through the set of values

The values we are comparing here are the x and y values

So

let us take a look at the options;

The first option is not a direct variation

For the first option, the rate of increase is not constant;

2/6 = 1/3 , 8/12 = 2/3 , 14/18 = 7/9

for the second;

the ratio is 1 to 1

for the third;

3/6 = 1/2 ; 6/12 = 1/2; 9/18 = 1/2

for the fourth;

2/6 = 1/3, 4/12 = 1/3 , 6/18 = 1/3

8 0
3 years ago
Calculate the sum of the multiples of 4 from 0 to 1000
allochka39001 [22]

Answer:

sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

Step-by-step explanation:

This problem can be solved using concept of arithmetic progression.

The sum of n term terms in arithmetic progression is given by

sum = (2a+(n-1)d)n/2

where

a is the first term

d is the common difference of arithmetic progression

_____________________________________________________

in the problem

series is multiple of 4 starting from 4 ending at 1000

so series will look like

series: 0,4,8,12,16..................1000

a is first term so

here a is 0

lets find d the common difference

common difference is given by nth term - (n-1)th term

lets take nth term as 8

so (n-1)th term = 4

Thus,

d = 8-4 = 4

d  can also be seen 4 intuitively as series is multiple of four.

_____________________________________________

let calculate value of n

we have last term as 1000

Nth term can be described

Nth term = 0+(n-1)d

1000 =   (n-1)4

=> 1000 = 4n -4

=> 1000 + 4= 4n

=> n = 1004/4 = 251

_____________________________________

now we have

n = 1000

a = 0

d = 4

so we can calculate sum of the series by using formula given above

sum = (2a+(n-1)d)n/2

       = (2*0 + (251-1)4)251/2

       = (250*4)251/2

     = 1000*251/2 = 500*251 = 125,500

Thus, sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

3 0
3 years ago
Write a expression to show 5 less than the sum of y and g
ddd [48]
Idk if this is correct but y+g>5 or 5<y+g
8 0
3 years ago
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