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Georgia [21]
3 years ago
7

Can you check if i did? (I think that stupid in math)

Mathematics
2 answers:
dimulka [17.4K]3 years ago
5 0

hey your answer is correct

Leto [7]3 years ago
4 0

Yes you did it right

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Solve this quadratic equation<br><img src="https://tex.z-dn.net/?f=3a%20%7B%7D%5E%7B2%7D%20-%204%20%2B%201" id="TexFormula1" tit
ivann1987 [24]

Answer:

1 and 1/3

Step-by-step explanation:

3a² -4a +1 = 0

3a²- 3a - a+ 1= 0

3a(a-1) - (a-1)= 0

(a-1)(3a -1)= 0

a-1= 0 ⇒ a= 1

3a - 1= 0 ⇒ 3a= 1 ⇒ a= 1/3

5 0
3 years ago
A box of fruit has four times more peaches than plums.
Ugo [173]

Answer:

The number of plums = 4

The number of peaches =  16

The number of nectarines =  1

Step-by-step explanation:

Let the number of peaches be = x

Let the number of nectarines be = y

Let the number of plums be = z

A box of fruit has four times more peaches than plums. This means that

The number of peaches = 4 X the number of plums.

i.e x = 4z

The box has 3 fewer nectarines than plums. This means that

Number of nectarines = number of plums - 3

i.e y = z - 3

If the box contains 21 pieces of fruit, this means that if we sum up all the peaches, nectarines, and plums in the box, we will get 21.

Peaches + Nectarines + Plums = 21

4z + z-3 + z = 21

6z =21 +3

z = 24/6

z = 4

Therefore, the number of plums = 4

The number of peaches = 4 X 4 = 16

The number of nectarines = 4 -3 = 1

7 0
3 years ago
If the cost of plastering 4 walls of a room at Rs 45 per sq. m is Rs 8100, find the area of the 4 walls of the room​
olga55 [171]

Step-by-step explanation:

Rs8,100 / (Rs45 per square meter)

= 180 square meters.

The area of the 4 walls of the room is 180 sq.m.

3 0
3 years ago
In order for you to answer the question correctly, please use the following image down below:
adell [148]

Answer:

36

Step-by-step explanation:

24^2 = (12)(12+x)

576 = 144 + 12x

432 = 12x

36 = x

7 0
3 years ago
Suppose that the universal set is U={1,2,3,4,5,6,7,8,9,10}. Express each of the following subsets with bit strings (of length 10
Vladimir [108]

Answer:

0011100000

1010010001

0111001110

Step-by-step explanation:

As the question is not complete, Here is the complete question.

Suppose that the universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Express each of these sets with bit strings where the ith bit in the string is 1 if i is in the set and 0 otherwise.

a) {3, 4, 5}

b) {1, 3, 6, 10}

c) {2, 3, 4, 7, 8, 9}.

So, we need to express a) b) and c) into bit strings.

Firstly, number of elements in the universal set represent the number of bits in the bit string.

Secondly, 1 = yes element is present in both universal set as well as in sub set.

0 = No, element is not present in sub set but present in universal set.

Hence, we have:

a) Sub set {3,4,5} = 0011100000  (As there are 3 1's which means only 3,4,5 are present in both universal set and subset.

Similarly,

b) Sub set {1, 3, 6, 10} = 1010010001

c) Sub set {2, 3, 4, 7, 8, 9} = 0111001110

5 0
3 years ago
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