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bixtya [17]
3 years ago
10

If a^ 1/n = n What is an equivalent form of 7? Show steps plz!

Mathematics
1 answer:
Scrat [10]3 years ago
6 0

Answer:

7⁷

Step-by-step explanation:

a^(1/7) = 7

a = 7⁷

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They definitely can be positive they can be negative and they can have an absolute value but I would choose they both can be positive and negative
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3 years ago
The angle of elevation to the top of a water tower from point A on the ground is 19.9°. From point B, 50.0 feet closer to the to
zepelin [54]

Answer:

Answer in terms of a trigonometric function :

h = \frac{20tan(19.9)}{0.4-tan(19.9)}

Answer in figures

h = 190.5 feet

Step-by-step explanation:

Consider the sketch attached below to better understand the problem.

Let x be the distance between point B and the base of the water tower.

tan (19.9)=\frac{h}{50+x} ---------------equation 1\\

tan (21.8)=\frac{h}{x}----------------equation 2

From equation 2,

x =\frac{h}{tan21.8}=\frac{h}{0.4}

substituting the value of x into equation 1, we get

tan (19.9)=\frac{h}{50+(\frac{h}{0.4} )}

tan 19.9=h\times \frac{0.4}{20+h}

cross multiplying,

20\times tan(19.9) +htan(19.9)=0.4h

20tan(19.9)= h(0.4-tan(19.9))

h= \frac{20tan (19.9)}{0.4-tan (19.9)}

The height of the tower is h= \frac{20tan (19.9)}{0.4-tan (19.9)} in terms of the trig function "Tan"

The equation can simply be evaluated to get the answer in figures since the angles are given in the question

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Find the inverse of the function.<br> y = 4x
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Step-by-step explanation:

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3 years ago
the height h(t) of a trianle is increasing at 2.5 cm/min, while it's area A(t) is also increasing at 4.7 cm2/min. at what rate i
nekit [7.7K]

Answer:

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Step-by-step explanation:

From Geometry we understand that area of triangle is determined by the following expression:

A = \frac{1}{2}\cdot b\cdot h (Eq. 1)

Where:

A - Area of the triangle, measured in square centimeters.

b - Base of the triangle, measured in centimeters.

h - Height of the triangle, measured in centimeters.

By Differential Calculus we deduce an expression for the rate of change of the area in time:

\frac{dA}{dt} = \frac{1}{2}\cdot \frac{db}{dt}\cdot h + \frac{1}{2}\cdot b \cdot \frac{dh}{dt} (Eq. 2)

Where:

\frac{dA}{dt} - Rate of change of area in time, measured in square centimeters per minute.

\frac{db}{dt} - Rate of change of base in time, measured in centimeters per minute.

\frac{dh}{dt} - Rate of change of height in time, measured in centimeters per minute.

Now we clear the rate of change of base in time within (Eq, 2):

\frac{1}{2}\cdot\frac{db}{dt}\cdot h =  \frac{dA}{dt}-\frac{1}{2}\cdot b\cdot \frac{dh}{dt}

\frac{db}{dt} = \frac{2}{h}\cdot \frac{dA}{dt} -\frac{b}{h}\cdot \frac{dh}{dt} (Eq. 3)

The base of the triangle can be found clearing respective variable within (Eq. 1):

b = \frac{2\cdot A}{h}

If we know that A = 130\,cm^{2}, h = 15\,cm, \frac{dh}{dt} = 2.5\,\frac{cm}{min} and \frac{dA}{dt} = 4.7\,\frac{cm^{2}}{min}, the rate of change of the base of the triangle in time is:

b = \frac{2\cdot (130\,cm^{2})}{15\,cm}

b = 17.333\,cm

\frac{db}{dt} = \left(\frac{2}{15\,cm}\right)\cdot \left(4.7\,\frac{cm^{2}}{min} \right) -\left(\frac{17.333\,cm}{15\,cm} \right)\cdot \left(2.5\,\frac{cm}{min} \right)

\frac{db}{dt} = -2.262\,\frac{cm}{min}

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

6 0
3 years ago
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