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erma4kov [3.2K]
3 years ago
9

A volleyball reaches its maximum height of 13 feet, 3 seconds after its served. Which of the following quadratics could model th

e height of the vollyball over time after it is served. Select all that apply.
A: f(x)=2x^2+12x+5
B: f(x)=-2x^2+12x-5
C: f(x)=-2x^2-12x+5
D: f(x)=-2(x-3)^2+13
E: f(x)=-2(x+3)^2+13
Mathematics
2 answers:
Ivahew [28]3 years ago
7 0

Answer:

B: f(x)=-2x^2+12x-5

and!!!!!!

D: f(x)=-2(x-3)^2+13

Step-by-step explanation:

b and are the only ones that give you the values 13 and 3

kykrilka [37]3 years ago
3 0
If it reaches its maximum height a t=3 its velocity must be zero at t=3

dy/dx=0 at t=3

dA/dx=4x+12=24 at t=3 so this does not apply

dB/dx=-4x+12=0 at t=3 and B=13 at t=3 so B applies

dC/dx=-4x-12=-24 at t=3 so this does not apply

dD/dx=-4x-12=-24 at t=3 so this does not apply

dE/dx=-4x-12=-24 at t=3 so this does not apply

So only quadratic B: reaches a maximum height of 13 feet at 3 seconds.
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Find the radius of the cylinder when volume is 304 cm^3 and height is 10 cm
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Answer:

<h2>3.11 cm</h2>

solution,

Volume of cylinder=304 cm^3

height=10 cm

Radius=?

Now,

volume = \pi  {r}^{2} h \\ or \: 304 = 3.14 \times  {r}^{2}  \times 10 \\ or \: 304 = 31.4 \times  {r}^{2}  \\ or \:  {r}^{2}  =  \frac{304}{31.4}  \\ or \:  {r}^{2}  = 9.68 \\ or \: r =   \sqrt{9.68}  \\ or \: r =  \sqrt{ {(3.11)}^{2} }  \\ r = 3.11 \: cm

Hope this helps..

Good luck on your assignment..

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