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ipn [44]
3 years ago
13

Identify the value of b. PLEASE HELP!!

Mathematics
1 answer:
Degger [83]3 years ago
7 0

Answer:

  b = 18

Step-by-step explanation:

From an external point, the products of distances to the near circle intercept and the far circle intercept are the same. For a tangent, such as AC, point A is both the near and far intercept point, so that product is the square of the length of AC.

  (AC)² = (CG)(CV)

  b² = 12·27 = 324 . . . . substitute known values

  b = √324 . . . . . . . . . . take the square root

  b = 18

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olga2289 [7]

Answer:

D. 9

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2 years ago
4z-(-3z) can you help me​
Korvikt [17]

Answer:

7z

Step-by-step explanation:

4z-(-3z).

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8 0
2 years ago
HELP ME PLEASE!!!
ser-zykov [4K]

parallel lines, have the same exact slope, hmmm what is the slope of y = -2/3 x + 1/3 anyway? well, low and behold, the equation is already in slope-intercept form, therefore


\bf ~~y=\stackrel{slope}{-\cfrac{2}{3}}x+\cfrac{1}{3}~~ has a slope of -2/3.


so we're really looking for a line whose slope is -2/3 and runs through 9,4.


\bf (\stackrel{x_1}{9}~,~\stackrel{y_1}{4})~\hspace{10em}slope =  m\implies -\cfrac{2}{3}\\\\\\\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-4=-\cfrac{2}{3}(x-9)\\\\\\y-4=-\cfrac{2}{3}x+6\implies y=-\cfrac{2}{3}x+10

8 0
3 years ago
Read 2 more answers
I need help solving this
pentagon [3]
Y=mx+b where m=slope=(dy/dx) and b=y-intercept (value of y when x=0)

You have two points...(1,-2),(3,2) so

m=(y2-y1)/(x2-x1)=(2--2)/(3-1)

m=4/2=2 now that you have the slope...

y=2x+b, you can use either point to solve for the y-intercept, I'll use (3,2)

2=2(3)+b

2=6+b

b=-4 so the line is:

y=2x-4
5 0
3 years ago
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