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natka813 [3]
2 years ago
9

SOMEONE ANSWER PLEASE!!!!!

Mathematics
2 answers:
Phoenix [80]2 years ago
6 0

Pilar started with 80 and adds 10 each week.

y= 10x + 80 (ten seashells • weeks + 80 she started with)

Marisol started with 0 and adds 20 each week.

y = 20x (no need to add + 0 because she started with nothing)

Inequality:

y = 10x + 80 < y = 20x

Weeks:

I would reccomend just plugging in numbers (for example if I put in 5 I would determine if it was too high or low then go to the next number.)

I plugged it into an online graph so I can’t show my work but the answer is 8 weeks.

Vadim26 [7]2 years ago
6 0

Answer:

8 weeks

Step-by-step explanation:

I had the same assigment and I got it ✅

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a classroom has triangular tables there is enough space at each side of a table to seat one child the tables in this class are a
Gekata [30.6K]

Answer:

15

Step-by-step explanation:

3 students can fit in one table. 5*3=15

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2 years ago
A 8-foot tall man is standing beside a 32-foot flagpole. The flagpole is
kipiarov [429]

Answer:

The flagpole's shadow is 16.875 feet longer than the man's shadow

Step-by-step explanation:

The total length of the shadow is expressed by taking its actual length by a factor that depends on the position of the sun which is constant for the man too. The expression is as follows;

Height of the shadow=actual height of the flagpole×factor

where;

length of the flagpole's shadow=22.5 feet

actual height of the flagpole=32 feet

factor=f

replacing;

22.5=32×f

32 f=22.5

f=22.5/32

f=0.703125

Using this factor in the expression below;

Length of man's shadow=actual height of man×factor

where;

length of man's shadow=m

actual height of man=8 feet

factor=0.703125

replacing;

length of man's shadow=8×0.703125=5.625 feet

Determine how much longer the flagpole's shadow is as follows;

flagpoles shadow-man's shadow=22.5-5.625=16.875 feet

The flagpole's shadow is 16.875 feet longer than the man's shadow

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