The answer is 8a + 12
here's my work
4(2a + 3)
4 times 2a is 8a
then 4 times 3 is 12
Answer:
How many different lines pass through a 3x3-point grid if a line only needs two points?
Step-by-step explanation:
The answer being (93)=9! 3! 6! =9⋅8⋅73⋅2⋅1=84 possible arrangements.
Use the given recursion and starting value of 
to find 
:
Do the same for 
and 
:
(That's not a mistake. This just tells you that the 2nd and 3rd iterates are very close together and have at least the same first 5 digits after the decimal.)
Answer:
The discriminant is the part under the square root in the quadratic formula, b²-4ac. If it is more than 0, the equation has two real solutions. If it's less than 0, there are no solutions. If it's equal to 0, there is one solution.
Brainliest please
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
