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Gwar [14]
3 years ago
11

Name 3 planes parallel to FL

Mathematics
2 answers:
3241004551 [841]3 years ago
8 0

Answer:

17)THE PLANES ARE <em><u>BCHI</u></em><em><u>,</u></em><em><u>DJIC</u></em><em><u>,</u></em><em><u>EDJK</u></em>

JulijaS [17]3 years ago
4 0

Answer:

I have answered. it is perfect answer

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How many tenths are equal to 1/2+4/5?
Artemon [7]
Answer: 13

1/2+4/5= 13/10 so the answer would be that 13 tenths equal 13/10
7 0
3 years ago
Today you will need to look at the following problem and explain what Susan did incorrectly.
lapo4ka [179]

Answer:

see explanation

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x - 3)² + (y + 4)² = 36 ← is in standard form

with (h, k) = (3, - 4 ) = centre and r = \sqrt{36} = 6

Susan interpreted the values of h and k incorrectly by using the values - 3 and 4 instead of taking the negative of them.

She also divided 36 by 2 , thus omitting the root of 36

4 0
3 years ago
I have no idea how to do this, this is just a wild guess
goldfiish [28.3K]
I think its $21 because since 72 was left over you subtract it from 240 and it leaves 168 which u divide by 8 and get $21
5 0
3 years ago
Read 2 more answers
Use a trigonometric ratio to find the value of x. round your answer to nearest tenth
Alenkasestr [34]
The trigonometry ratio that we shall use to solve the question will be:
tan θ=opposite/adjacent
where:
opposite=8.9 cm
adjacent =x cm
θ=55°
plugging the values and simplifying we obtain:
tan 55=8.9/x
thus
x=8.9/tan55
x=6.23 cm~6.2 cm
Answer: A
3 0
4 years ago
Read 2 more answers
There are x number of students at helms. If the number of students increases by 7.8% each year, how many students will be there
vodomira [7]

There will be 1.078x students next year and equation is number of students in next year = x + 7.8% of x

<h3><u>Solution:</u></h3>

Given, There are "x" number of students at helms.  

The number of students increases by 7.8% each year which means if there "x" number of students in present year, then the number of students in next year will be x + 7.8% of x

Number of students in next year = number of students in present year + increased number of students.

\begin{array}{l}{\text { Number of students in next year }=x+7.8 \% \text { of } x} \\\\ {\text { Number of students in next year }=x\left(1+\frac{7.8}{100}\right)} \\\\ {\text { Number of students in next year }=x(1+0.078)=1.078 x}\end{array}

Thus there will be 1.078x students in next year

3 0
4 years ago
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